In loop functions.py, define a function named permutations that takes two paramters, n and r, in that order. This function returns the number of different permutations of length r from set of size n. Essentially to calculate these permutations, the function should compute the product (n - r+1)*(n-r+2)*(n-r+3)*...*(n-2)*(n-1) or n!/(n-r)!. No if statements or built in math functions should be used. For or while loops are best reccomended.
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In loop functions.py, define a function named permutations that takes two paramters, n and r, in that order. This function returns the number of different permutations of length r from set of size n. Essentially to calculate these permutations, the function should compute the product
(n - r+1)*(n-r+2)*(n-r+3)*...*(n-2)*(n-1) or n!/(n-r)!.
No if statements or built in math functions should be used. For or while loops are best reccomended.
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- solve in assembley language, MIPS Square Root Calculation: Newton’s iterative method can be used to approximate the square rootof a number x. Let the initial guess be 1. Then each new guess can be computed as follows:guess = ((x/guess) + guess) / 2; Write a function called square_root that receives a double-precision parameter x, computes,and returns the approximated value of the square root of x. Write a loop that repeats 20 timesand computes 20 guess values, then returns the final guess after 20 iterations. Use the MIPSfloating-point register convention (Section 9.6) to pass the parameter x and to return thefunction result. All computation should be done using double-precision floating-pointinstructions and registers. Compare the result of the sqrt.d instruction against the result ofyour square_root function. What is the error in absolute value?Define a function in loop_functions.py named count_collatz that takes a single paramater named a_0. This function takes a positive intenger a_0 and returns the minimum number of iterations required to find a term equal to 1. In other words, this function counts how many terms it takes to reach 1. Look at the list below for examples. You may use if statements but for and while loops are preferred.The Fibonacci sequence is a famous sequence in mathematics. The first element in the sequence is 0 and the second element is 1. The nth element is defined as Fn = Fn-1 + Fn-2- Implement the fib function, which takes an integer n and returns the n th Fibonacci number. Use a while loop in your solution. def fib(n): """Returns the nth Fibonacci number. >>> fib (0) 0 >>> fib (1) 1 >>> fib(2) 1 >>> fib(3) 2 >>> fib(4) 3 >>> fib(5) 5 >>> fib(6) 8 >>> fib (100) 354224848179261915075 "*** YOUR CODE HERE ***"
- Code in Python Write a function, print_integers_less_than(n), which takes an integer parameter n and prints each integer k which is at least 0 and is less than n, in ascending order. Hint: use a simple for loop. For example: Test Result print_integers_less_than(2) 0 1 print_integers_less_than(5) 0 1 2 3 4 print_integers_less_than(-3)CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021Q11/ A function f(t) is said to be even if: Oa) f(t) = f(-t) Ob) f(t) = -f(-t) Oc) f(t) # f(-t) %3D Od) None of these
- Going missing Some calculations involving blank values may give different results to what you might expect. For example, when you pass a blank value into the AND() function, it is treated as TRUE. This is often unhelpful. To make blanks behave in a sensible way in calculations, you must first convert them to be "not available" using NA(). This function takes no inputs, and returns a missing value. To convert a blank value to a missing value, use this pattern. =IF(ISBLANK(cell), NA(), cell) Instruction In column H, use AND() to find women who have kids and get benefits. In column I, convert the blanks in column G to missing values. In column J, again find women who have kids and get benefits, this time using column I rather than G. please show the formula used to "has kids and gets benefits" , "gets benefits with missing values", has kids and gets benefits". Thank you Is non-white Has over 12 years of school? Is married? Has kids? Has young kids? Is head of household? Gets…// Description: Write a program that outputs a root of a given function f(x) by using a bi-section method. // f(x) = x3 + 5x2 +7x +2Rolling a single six-sided die produces a random number between 1 and 6 with a uniform distribution. Rolling two dice produces a number between 2 and 12 with a binomial distribution. In this lab you will simulate a number of dice rolls and graph the number of occurrences of each value. 1) Create a function called rollDie() that takes no parameters, and returns a random value between 1 and 6. Do not seed the random number generator in this function. int rollDie() 2) Create a function called initArray() that takes a data array and the size of the array as parameters and fills each element with the summed results of rolling two dice. Do not assume that the data array has been initialized. void initArray(int data[], int size) 3) Create a function called sortArray() that takes an array and the size of the array as parameters, and sorts the array using the sediment sort. void sortArray(int data[], int size) The sediment sort works as follows: start with the second element in the array if…
- Write a recursive function named largestDigit that accepts an integer parameter and returns the largest digit value that appears in that integer. Your function should work for both positive and negative numbers. If a number contains only a single digit, that digit's value is by definition the largest. You must not use any loops; you also cannot use the string type or any library functions. Your function must be recursive. Complete the following file: largestDigit.cpp 2 // You may use this helper function 3 int max(int a, int b) { return a < b ? b : a; } 4 5 int largestDigit(int n) if((n<0) && (n/10 if(n<0) n = 0)) return n; 8 -n; static int maxi 9 n%10; 0) return maxi; maxi = max(maxi, n%10); return largestDigit(n/10); = 10 if((n/10) 11 12 13 14 15 16 } Submit Calling with Arguments Name Arguments Actual Expected pass largestDigit 135725 7 7 pass largestDigit 111211 2 2 fail largestDigit 100000 1 pass largestDigit 4530021 5 pass largestDigit 7639852 fail largestDigit 76352 6 pass…The numpy module contains functions to generate random permutations. Given a non-negative integer n, every permutation of 2n numbers can be turned into a matching by taking the first half of the permutation entries (i.e., the first n numbers) and connecting each of them to the corresponding entry in the second half (i.e., the last n numbers). Use this method to write a function random_matching that takes n and returns a randomly selected matching of 2n numbers in the form of a list of n tuples, where each tuple contains two integers. Note: Ensure that the tuples are returned such that the first integer is less than the second integer. To demonstrate that your code works, draw the arc diagrams for five randomly chosen matchings of 20 numbers.CodeW X bFor fun X C Solved x b Answer + x https://codeworko... CodeWorkout X265: Recursion Programmlng Exercise: GCD The greatest common divisor (GCD) for a pair of numbers is the largest positive integer that divides both numbers without remainder. For function GCD , write the missing base case condition and action. This function will compute the greatest common divisor of x and y.You can assume that x and y are both positive integers and that x > y. Greatest common divisor is computed as follows: = x and GCD(x, y) = GCD(y, x % y). Examples: GCD (6, 4) -> 2 Your An swer: 1 public int GCD(int x, int y) { if > { 2. > 3. } else { 4. return GCD(y, x % y); 9. { 7. 1:09 AM 50°F Clear 1V 1. 12/4/2021 甲