In a railroad classification yard, a 69-Mg freight car moving at 1.2 m /s at A encounters a retarder section of track at B which exerts a retarding force of 48 kN on the car in the direction opposite to motion. Over what distance x should the retarder be activated in order to limit the speed of the car to 2.9 m /s at C? 143 m A 3.9 m B (Vertical scale exaggerated)

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Chapter1: Units, Trigonometry. And Vectors
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2. How much work is done by gravity as the car moves from A to C?


Answer: Ug =  kN●m
 
 
Calculate the kinetic energies at A and C;
Answers:
TA =
49680
kg m2/s2
Tc =
kg m2/s2
290145
How much work is done by gravity as the car moves from A to C?
Answer: Ug = i
kN•m
Transcribed Image Text:Calculate the kinetic energies at A and C; Answers: TA = 49680 kg m2/s2 Tc = kg m2/s2 290145 How much work is done by gravity as the car moves from A to C? Answer: Ug = i kN•m
In a railroad classification yard, a 69-Mg freight car moving at 1.2 m /s at A encounters a retarder section of track at B which exerts a
retarding force of 48 kN on the car in the direction opposite to motion. Over what distance x should the retarder be activated in order
to limit the speed of the car to 2.9 m/s at C?
143 m
3.9 m
A
(Vertical scale exaggerated)
C
Part 1
Calculate the kinetic energies at A and C;
Answers:
TA =
i
kg m?/s2
Tc=
kg m2/s2
i
Transcribed Image Text:In a railroad classification yard, a 69-Mg freight car moving at 1.2 m /s at A encounters a retarder section of track at B which exerts a retarding force of 48 kN on the car in the direction opposite to motion. Over what distance x should the retarder be activated in order to limit the speed of the car to 2.9 m/s at C? 143 m 3.9 m A (Vertical scale exaggerated) C Part 1 Calculate the kinetic energies at A and C; Answers: TA = i kg m?/s2 Tc= kg m2/s2 i
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