In a poll of 1000 randomly selected voters in a local election 170 voters were against school bond measures what is the sample proportion what is the margin of error for the 99% confidence level Confidence Level - 0.99 = 2.576

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Q: Find the midrange for the following group of data items.   84, 85, 86, 90, 89, 85

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Q: 25. How did you make the determination in Question #24?

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A: Given that  Sample size n =287 Favorable cases x =190 Sample proportion p^=x/n =190/287 =0.6620

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