Imagine a tree in which each node can have up to a hundred children. Write an analog of the TreeNode declaration that can be used to represent the nodes of such a tree. A declaration such as TreeNode {int value;TreeNode *child1;TreeNode *child2;TreeNode *child3;... };
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Imagine a tree in which each node can have up to a hundred children. Write an analog of the TreeNode declaration that can be used to represent the nodes of such a tree. A declaration such as
TreeNode
{
int value;
TreeNode *child1;
TreeNode *child2;
TreeNode *child3;
.
.
. };
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- C++ PROGRAMMING Please implement these 2 methods for the node where: •int get_depth(): Returns the depth of the node. •int get_height(): Returns the height of the node. Initial code to be completed: Note: Do not add new member variables for the depth and height. struct node { node* parent; node* right; node* left; int element; int get_depth() { return 0; } int get_height() { return 0; }};please convert to C languange #include<bits/stdc++.h>using namespace std; class tree{ //tree node public: int data; tree *left; tree *right;}; bool hasRootToLeafSum(tree *root, int s){ bool path=false; //declare boolean variable path //base condition checking if(root==NULL && s==0) return true; s-=root->data; //subtract current root value //checking whether leaf node reached and remaining sum =0 if(s==0 && root->left==NULL && root->right==NULL) return true; //recursively done for both subtrees if(root->left){//for left subtree path=path||hasRootToLeafSum(root->left, s); } if(root->right){//for right subtree path=path||hasRootToLeafSum(root->right, s); } return path;} tree* newnode(int data){ //creating new nodes tree* node = (tree*)malloc(sizeof(tree)); node->data = data; node->left = NULL; node->right = NULL;…C++ DATA STRUCTURES Implement the TNode and Tree classes. The TNode class will include a data item name of type string,which will represent a person’s name. Yes, you got it right, we are going to implement a family tree!Please note that this is not a Binary Tree. Write the methods for inserting nodes into the tree,searching for a node in the tree, and performing pre-order and post-order traversals.The insert method should take two strings as input. The second string will be added as a child node tothe parent node represented by the first string. Hint: The TNode class will need to have two TNode pointers in addition to the name data member:TNode *sibling will point to the next sibling of this node, and TNode *child will represent the first child ofthis node. You see two linked lists here??? Yes! You’ll need to use the linked lists
- Modify the given code to accept float instead of int as a coefficient in C LANGUAGE: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 =…C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(left(P) != NULL && right(P) != NULL){ if(left(P) == p){ return right(P); } return left(P); } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<<endl; return NULL; } root = create_node(e,NULL); size++; return root; } node* addLeft(node* p, int e) { if(p->left == NULL){ node* newLeft =…Course: Data Structure and Algorithims Language: Java Kindly make the program in 2 hours. Task is well explained. You have to make the proogram properly in Java and attach output screen with program: Restriction: Prototype cannot be change you have to make program by using given prototype. TAsk: classBSTNode { Node left; Node right; int data; publicBSTNode(int _data);// assign data to_data and assign left and right node to null } class BST { BSTNoderoot; public BST();// assign root to null void insert(int data);// this function insert the data in tree which maintain property of BST boolean Search(int key); this function search the data in bst and return true if key is found else return false public void EvenPrint(Node n)// this function only print the data which are even, make this function resursive public void OddPrint(Node n)// this function only print the data which are odd, make this function resursive public void PrimePrint(Node n)// this function only…
- c++ programming Complete all these 2 methods for the node Node methods •int get_depth(): Returns the depth of the node. •int get_height(): Returns the height of the node. Initial code to be completed:struct node { node* parent; node* right; node* left; int element; int get_depth() { return 0; } int get_height() { return 0; }};C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(left(P) != NULL && right(P) != NULL){ if(left(P) == p){ return right(P); } return left(P); } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<<endl; return NULL; } root = create_node(e,NULL); size++; return root; } node* addLeft(node* p, int e) {…CO LL * Question Completion Status: QUESTION 3 Write a recursive function, OnlyChild(..), that returns the number of nodes in a binary tree that has only one child. Consider binaryTreeNode structure is defined as the following. struct binaryTreeNode int info; binaryTreeNode *llink: binaryTreeNode *rlink; The function is declared as the following. You must write the function as a recursive function. You will not get any credits if a non-recursive solution is used. int OnlyChild(binaryTreeNode *p); For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). Paragraph Arial 10pt B. ^三へ三 三山 三Ex? X2 = E E E 9 Click Save and Submit to save and submit. Click Save All Answers to save all ansuwers. Is E English (United States) Focus || 15 stv MacBook Air D00 O00 F4 F5 F8 64
- C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE CODE IDEAIt doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* findNewRoot(node* curr) { if(curr->left == NULL) { return curr; } return findNewRoot(curr->left); } bool remove(int num) { bool isPresent = search(num); if(isPresent){ bool rem = false; int numOfChild; node* realRoot = search_node(root,num); if(realRoot->left == NULL && realRoot->right == NULL) { numOfChild = 0; } else if((realRoot->left != NULL && realRoot->right == NULL) || (realRoot->left == NULL && realRoot->right != NULL) ) { numOfChild = 1; } else if(realRoot->left != NULL && realRoot->right != NULL) { numOfChild = 2; } if(numOfChild == 0) { bool leadRoot = false; if(realRoot == root) {…Computer Science QuestionConsider the adjacency list (list of neighbors) data structure for representing a graph. struct node{int data; node * next;};class Graph { …………private:node neighborList[30];int last;};Write a method to print the neighbors of a given node n, void Graph::print(int n){??????}C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* findNewRoot(node* curr) { if(curr->left == NULL) { return curr; } return findNewRoot(curr->left); } bool remove(int num) { bool isPresent = search(num); if(isPresent){ bool rem = false; int numOfChild; node* realRoot = search_node(root,num); if(realRoot->left == NULL && realRoot->right == NULL) { numOfChild = 0; } else if((realRoot->left != NULL && realRoot->right == NULL) || (realRoot->left == NULL && realRoot->right != NULL) ) { numOfChild = 1; } else if(realRoot->left != NULL && realRoot->right != NULL) { numOfChild = 2; } if(numOfChild == 0) { bool leadRoot = false; if(realRoot…
