Help me II. Rate of a ReactionTime (min)Concentration of Phenyl Acetate (M)1.05.21.54.92.04.54.03.44.53.15.03.07.02.2(a) Using Excel, prepare a graph of concentration vs. time using the data above. Include all of thepertinent data and components that must accompany this graph as described in the Background Video.(b) Using Excel, prepare a graph of 1/concentration vs. time using the same data. Include all of thepertinent data and components that must accompany this graph as described in the Background Video.(c) Using Excel, prepare a graph of In concentration vs. time using the data. Include all of the pertinentdata and components that must accompany this graph as described in the Background Video.(d) State which graph shows the most linear relationship and explain how you know that this graph ismore linear than the graphs in this group.

The time v/s concentration of reactant data given is,

Answered: II. Rate of a Reaction Time (min)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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1 Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes under identical storage conditions at 37°C for 3 months. If both drugs degrade by first-order, which drug will retain the highest percentage of initial concentration? (a) Drug A (b) Drug B (c) They will be the same.
The following data was collected for the reaction between ethoxide and methyl iodide T(°C) Rate (1/s) T (K) 1/T (1/K) In (rate) 168 273.15 0.00366 5.12 6 354 279.15 0.00358 5.87 12 735 285.15 0.00351 6.60 18 1463 291.15 0.00343 7.29 24 3010 297.15 0.00337 8.01 30 6250 303.15 0.00330 8.74 A plot of In (rate) vs. 1/T using the above table was made and is shown below, and a linear regression line fitted to the data. Using the provided graph, estimate the activation energy (kJ/mol) of the reaction between ethoxide and methyl iodide. Enter your number using 2 decimal places without unit. Gas constant is R = 8.3144598 J. mol 1. K-1. In(k) vs 1/T 9.30 8.80 8.30 7.80 y = -9930.5x + 41.445 R² = 0.9992 2 7.30 6.80 6.30 5.80 5.30 4.80 0.00325 0.00330 0.00335 0.00340 0.00345 0.00350 0.00355 0.00360 0.00365 0.00370 1/T (1/K) Ln(k)
the mean time, the rate, [S₂O3] in the reaction may label clear outliers the mean) as such and e calculation. on mixtures NH4)2SO4 (NH4)2S2O8| (mL) (mL) 1.50 0.50 1.50 0.50 1.00 1.00 1.00 1.00 following reagents are um iodide ium persulfate m thiosulfate um nitrate ium sulfate odide in the solution in the Answer: 0.050 M • Determination of the rate law follows the protocol in ref. (5). with one difference. A reactant order (rate law exponent) will be calculated twice using two different pairs of determinations (e.g. determinations 1 & 2 and determinations 3 & 4). Then the mean is taken of both values and reported as order. This is done for each reactant. This additional step allows us to include more data and reduce experimental error. Practice Problem 2: The rate of a reaction CO(g) +3H₂(g)→ CH4(g) + H₂O(g) was determined at 25 °C. From the following data, determine a) the mean reaction order with respect to CO b) the mean reaction order with respect to H₂ c) the overall rate order d)…
In any manufacturing process, reaction monitoring ensures that a chemical reaction proceeds as expected. Table 1 shows the monitoring data for the formation of chlorohexane, collected using a technique called gas chromatography. Note that the concentrations of the chlorohexane solutions are given in millimoles per litre (mmol l–1). The abbreviation mM (millimolar) is frequently used. Plot a graph of the data in Table 1. The graph should be drawn on graph paper or use fine grid if it’s drawn on Excel. Elapsed Time/Hours Concentration of Chlorohexane/mM 0 0 2 40 4 65 6 80 8 90 10 95 12 99
Run Reactants Temperature (Celsius) Initial Rate (kPa/s) 1 10 ml 3% H2O2 = 5ml 0.5M KI 23.0 0.0798 2 5ml 3% H2O2 = 5ml 0.5 M KI 23.0 0.0391 3 5ml 3% H2O2 + 10ml 0.5 M KI 23.0 0.0794 Run Initial Rate (mol/L*s) [H2O2] after mixing [I-] after mixing 1 3.24 x 10^-5 0.147 M 0.0417 M 2 1.59 x 10^-5 0.0733 M 0.417 M 3 3.23 x 10^-5 0.0733 M 0.0833 M Calculate the rate law for the reaction
Route 1:RME = 82.92%MI= 1.34 Route 2RME = 22.84%MI = 18.15 Route 3RME = 57.34%MI = 1.89 Compare the value of Reaction Mass Efficiency (RME) and Mass Intensity (MI) generally, and choose which metrics is more significant in green measurement. Justify your answer.
Tools Help O Mode Delay 7. (2 Points) Let's try one more but add the theoretical yield concept. Consider the following UNBALANCED equation: NO(g) + H2(g) → NH3(g) + H,0(g) If you start with 89.3 g NO(g) and 28.6 g H2(g), find the theoretical yield of ammonia. Express your answer in grams. 11 (2 points) Looking at the bottom of her tea cup, Prof. Trelawney suddenly has a revelation! 69°F Mostly DELL B
The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k = Ae-E/RT where R is the gas constant (8.314 J/mol K), A is a constant called the frequency factor, and Da is the activation energy for the reaction. However, a more practical form of this equation IS In = (1-12) Ea R which is mathmatically equivalent to In Ea F (1/2 R T₂ k2 T1 where ki and k2 are the rate constants for a single reaction at two different absolute temperatures (T₁ and T₂). ▼ Part A The activation energy of a certain reaction is 42.1 kJ/mol. At 20 °C, the rate constant is 0.0150s¹. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. T₂ = Submit Part B Value k₂ = Request Answer Submit Given that the initial rate constant is 0.0150s¹ at an initial temperature of 20 °C, what would the rate constant be at a temperature of 200. °C for the same reaction described in Part…
An experiment was performed in a similar manner as Experiment 4 (The Hydrolysis of t-Butyl Chloride). The following data was obtained: Total Time (s) Volume NaOH Titrant used (mL) 46 2.01 91 3.97 131 5.98 175 8.03 220 10.00 266 11.99 311 14.01 357 15.97 401 17.98 450 20.02 Final Volume NaOH to fully react sample: 85.01 mL Assume the proposed reaction mechanism in the experimental procedure is correct. Based on the above measurements, how many minutes would it take for the solution to reach 81.0% completion? Round your final answer to two decimal places.
1:41 1 .5Gc NH, (aq) B) H+ (aq) + OH¯ (aq) → H₂O (1) C) NH3 (aq) + HI (aq) → NHÂI (aq) D) NH₂ (aq) → NH3 (aq) + H+ (aq) Tap here or pull up for additional resources
The plot below shows the concentration of reactant A during a chemical reaction (A (ag) + B(ag) C (aq) + D (aq)) as a function of time. This reaction is taking place at 310 K A and B are aqueous solutes Estimate the instantaneous rate at 80 seconds. Give your answer with units of M/s. 0.50 (A) (M) 0.45 0.40 0.35 0.30 0.25 0.20 0.15 0.10 005 0.00 0 20 Type your answer. 40 60 time (s) 80 100 120 140
1-arr In a study of the decomposition of dinitrogen pentoxide in carbon tetrachloride solution at 30 °C N2O5- →2 NO2 + ½ O2 the concentration of N,O5 was followed as a function of time. It was found that a graph of In[N2O5] versus time in minutes gave a straight line with a slope of -6.31×10* min and a y- intercept of -1.34 . Based on this plot, the reaction O order in N,0g and the rate constant for the reaction is min-1. zero first second

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