Q: In this situation, n = 2.1 and θ₀ = 26°. Calculate θᵣ, the reflected angle.
A: According to the law of reflection, the angle of incidence will be the same as angle of reflection.
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A: n = c/v =3 × 10 8 m/s/2.3 × 10 8 m/s =1.30
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Q: A certain kind of glass has n blue = 1.650 for blue light and n red = 1.610 for red light. If a beam…
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A: Given data: Speed of light in given substance V = 1.4 × 108 m/s Speed of light in vacuum (c) = 3 ×…
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Q: Compute the index of refraction for the substance where lightpropagates with speed v = 2.4 × 10 8…
A: Refractive index defined as the ratio of speed of light in vaccum to the velocity of light in the…
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A: Given, lens type is concave Focal length, f= 9.7 cm Object distance , u=41.8 cm Image distance v=?…
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Q: 45° a? 90° 45° B? 45°
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A: solution of above step, given in below step with explaination.
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A: Given that: y1=0.25"d1=28"d2= 80"
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A: Write the given values of the problem- Speed of the light in air is (v1) v1=3.0×108 ms-1
Q: If the index of refraction of a certain glass is 1.50, and the angle of refraction is 20 for a ray…
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Q: Does the apparent depth of a tank of water change if viewed obliquely? If so, does the apparent…
A: Yes, the apparent depth of a tank of water changes if viewed obliquely.
Q: A ray of light travels across a liquid-to-air. If the index of refraction for the liquid is, 1.33 .…
A: Refractive index of liquid = 1.33
Q: A certain kind of glass has nue = 1.650 for blue light and = 1.610 for red light. If a beam of white…
A: Refraction is the phenomenon by virtue of which when a ray of light passes from a rarer medium to…
Q: ray of light crosses the boundary between some substance with n = 1.58 and air, going from the…
A: ray of light crosses the boundary between some substance with n = 1.58 and air, going from the…
Q: A man shines a flashlight from a boat into the water, illuminating a rock as in the figure below.…
A: Solution:
Q: A lens has a focal length of 28 cm and a diameter of 4.0 cm. What is the f - number of the lens?
A: Given:Focal length of the lens = 28 cmDiameter of the lens = 4 cm
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A: Given refractive index of medium = n2 = 1.54 Refractive index of air = n1= 1 Angle of incidence =…
Q: How can the equation for the critical angle be derived from Snells Law?
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Q: A man shines a flashlight from a boat into the water, illuminating a rock as in the figure below.…
A: Given data: The depth of the water is, a= 2.52 m The distance of rock from normal is, b= 1.07 m…
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Q: An incident striko a glais (n=1.52) with an angle f 38° to the surface OF a illastrate with label…
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A: Given: The angle of the incident with normal is 42o.
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If the critical angle = 48, what does n equal?
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- Find the sum y of the following quantities: y1 = 10 sin vt and y2 = 8.0 sin(vt + 30°).If ϕ = 90° − θ, what is the value of sin2 ϕ + sin2 θ?One newly discovered light particle has a mass of m and property q. Suppose it moves within the vicinity of an extremely heavy (fixed in place) particle with a property Q and mass M. When the light particle is xi distance from the heavy particle, it is moving directly away from the heavy particle with a speed of vi. a) What is the lighter particle's speed when it is xf away from the heavy particle? Amım2 Consider a new expression for gravitation potential energy as: PEgrav where A is a constant, m1 and m2 are the masses of the two objects, and r r is the distance between them. Moreover, the new particle has an additional interaction with the heavy particle through the following force expression Ob 4TTE, p2 1 Fnew where Eo is a constant that is read as epsilon subscript 0, q and Q are their new properties, r is the distance between the new particle and the heavy particle. Solution: We may solve this using two approaches. One involves the Newton's Laws and the other involving Work-Energy…
- On a clear day a tiny fish hides under water (nwater =1.38) from an osprey under a circular leaf that has a diameter of 0.215 m. What is the maximum depth below the leaf that the fish can be so that it could not be spotted by the ospray? h Provide your answer in meters with a precision of four places after the decimal.For A 3D х ӑх+уӑy+zaz and B — 2x aх + Зу ӑу + 4z dz Find the following a) C = Ā×B b) at (1,2,3) find |Ā× B|,angle 0 between AandĒ, and ān с) D%3D A.B at (1,2,3)Use y - yı = m(x – x) to find the equation of the line that contains (a, b) and is perpendicular to the line -er + d. Leave the answer (equation) in the form y %3D тх + b. y
- 39. A woman stands at a horizontal distance x from a mountain S and measures the angle of elevation of the mountaintop above the horizontal as 0. After walking a distance di closer to the moungain on level ground, she finds the angle to be d. Find a general equation for the height y of the mountain in terms of d, , and 8, neglecting the height of her eyes above the ground.Given: A: A₂ = 43.4, Ay = 35.4 B: (B= 16.3 OB = 39.7° (a) Calculate the x-components and y-components of B. B₁ = 9. By= (b) Calculate the length and direction of Ã. Assume angles are measured from the +x-axis with counter-clockwise as positive angles and clockwise as negative angles. A = 9- 0A= (c) Calculate the components of the vector sum of A + B = Ć: CT= 9. 0c= 9. Cy= (d) Calculate the length and direction of C: Assume angles are measured from the +x-axis with counter-clockwise as positive angles and clockwise as negative angles. C= 9- 0 9.Help me solve the following table. Angle of incidence (?i) is 65, angle uncertainty (??) is 1. I tried (1*2.4919*pi)/180 * ((1/tan65)+(1/tan22)) = ?n, but it said the answer was wrong, and i don't know how to continue from there. So, the answer cannot be 4.8838.
- Find the expression for angle cosθ ?A driver can see the sunset at an angle of (R.I. of water = 4/3) (a) sin-¹ (4/3) (c) sin-¹ (1/4) (b) (d) sin-¹ (1/3) sin¹ (3/4)Question to answer: Can you explain to me how did the expert came up with their conclusions on each angle. Specially the 75 on the upper part. I am confused how did they arrived with those values when 125 and 65 degrees are only given in the problem. 1st pic is the problem and next is the solution annd the FBD. Please, I need ur help immediately. Thank you so much!