If AX = 1001H and DX = 20FFH list the sum and the contents of each flag register bit(C, A, S, Z, and O) after the ADD AX,DX instruction executes *
Q: For a MIPS lw instruction, ALU needs to perform _______. a) addition b) subtraction c)…
A: a) addition Option a) is the correct option.
Q: 1. If AX = 1001H and DX = 20FFH, list the sum and the contents of each flag register bit (C, A, S,…
A: Flag registers are used for special purposes to hold resulting value after the arithmetic operations…
Q: if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical…
A: The answer will be:- 6234H
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A: Dear Student, The next opcode will be fetched from the relative address of the current opcode…
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A: Answer :
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A: Answer: I have given answered in the handwritten format in brief explanation.
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A: Please check the step 2 for solution
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A: answer is option f f.1000. the branch instruction should be 1000
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A: Let us see the answer below.
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A: The Answer is
Q: Q: Compute the physical address for the specified operand in each of the following instructions. The…
A: Given data: CSCS=0A00H DSDS=0B00H SSSS=0D00H SISI=0FF0H DIDI=00B0H BPBP=00EAH IPIP=0000H LIST=00F0H…
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A: Answer: I have given answered in the handwritten format in brief explanation.
Q: Assuming that (AX=10H), (BX=100H), (DX=1000H) What happens if XLAT instruction is executed ?
A: XLAT moves a byte from address (DS*10+(BX +AL)) to the register AL.
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A: ANSWER:-
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Q: Q: Compute the physical address for the specified operand in each of the following instructions. The…
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- BX=FFFF, after instruction INC BX is executed, CF ||(d) The table below shows the ALUcontrol signal of the datapath we discussed in class. Instruction Funct ALU Орсode ALUop ALU action operation field control Iw 00 load word XXXXXX add 0010 Sw 00 store word XXXXXX add 0010 beq 01 branch equal subtract 0110 XXXXXX R-type 10 add 100000 add 0010 R-type 10 subtract 100010 subtract 0110 R-type 10 AND 100100 AND 0000 R-type 10 OR 100101 OR 0001 R-type 10 set on less than 101010 set on less than 0111 You want to add the bne instruction into the datapath, which already includes the required hardware for the instruction. Write out the ALUop for bne and how you can determine whether the bne results in the branch to be taken.Bus d'adresse Ox0 A7 0 A6 0 AS Oxo 0 A4 0 A3 0 A2 0 A1 Lecture Bus de contrôle Écriture AO Bus de données Mémoire d'Instructions Adr Adr Ctr Ctr Ctr Ox Mémoire de données Clavier Écran CD 0 EN Data Data EN Data EN Data EN Write the instruction STR R2, [R3] in hexadecimal (using 2 bytes). АО A1 DO D1 D d u r D3 D2 09
- Memory 12200 12201 12202 12203 12204 Content %D AA EE FF 22 What result is produced in the destination operand by execution the following instruction? a- LEA SI[DI+Bx+5] b- LDS SI.[200]SP=1239H, SS=9876H, the physical address is AAAFOH Non of them 1BC06H 0AAAFH 99999H if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical address is 6324H O 4244H 4234H 6234H 6243H OUsing the following data definitions: bytel BYTE byte2 BYTE word1 WORD word2 WORD 3 OFFh, 1, 2 14h OFFFFh, 1, 2 word3 SWORD 7FFFh, 8000h word4 SWORD 9000h dword1 DWORD 10h, 20h, 30h, 40h dArray DWORD 10 DUP (?) Write an instruction that moves the lower 8 bits of word2 into the AL register.
- The instruction used to copy two bytes from the stack to the Flags Register is: SAHF CMC PUSHF LAHF POPF STC The instruction that can be used to exchange between BL and BH is: * ROL BX, 4 ROL BL, BH ROR BX, 16 ROR BH, BL ROR BX, 8 RCR BX, 8 RCR BL BH To divide the signed number in AX by 2 using shift operations, which instruction should be used: * SAL AX, 1 SHL AX, 2 SAL AX, 2 SHL AX, 1 SHR AX, 1 SHR AX, 2 SAR AX, 1 SAR AX, 2The instruction that pushes the contents of the specified register/memory location on to the stack is PUSHF O POPF O PUSH O POP O This flag is used by the instructions that perform BCD .(binary coded decimal) arithmetic Carry Flag O Parity Flag O Auxiliary Carry Flag the Direction Flag OWhat is the effective address that is targeted by the store instruction whose code word in binary is:101011 01000 10001 1111 1111 1111 1000Assume [$t0]=0x400C
- Address Instruction Ох180 CALL tstFun Ox642 testFun: MOVLW Ox90 Using the above code segment, enter Machine code stored in location Ox181 and Ox180: Ox Machine code stored in location Ox183 and Ox182: 0xTompute the physical address for the specified operand in each of the following instructions. egister contents and variable are as follows: (CS)=0A00H, (DS)=OB0OH, (SS)=OD00H, S)=OFFOH, (DI)=00BOH, (BP)=00EAH and (UP)=0000H, LIST=00FOH, AX=4020H, BX=2500H. 1) Destination operand of the instruction MOV LIST (BP+DI], AX 2) Source operand of the instruction MOV CL, [BX+200H] 3) Destination operand of the instruction MOV [DI+6400H], DX 4) Source operand of the instruction MOV AL, [BP+SI-400H] 5) Destination operand of the instruction MOV [DI+SP], AX 6) Source operand of the instruction MOV CL, [SP+200H] 7) Destination operand of the instruction MOV [BX+DI+6400H], CX 8) Source operand of the instruction MOV AL , [BP-0200H] 9) Destination operand of the instruction MOV [SI], AX 10) Destination operand of the instruction MOV [BX][DI]+0400H,AL 11) Source operand of the instruction MOV AX, [BP+200H] 12) Source operand of the instruction MOV AL, [SI-0100H] 13) Destination operand of the…1. T/F - if (B)=006000 (PC)=003600 (X)=000090, for the machine instruction 0x032026, the target address is 003000.2. T/F – PC register stores the return address for subroutine jump.3. T/F – S register contains a variety of information such as condition code.4. T/F – INPUT WORD 1034 – This means Operating system should reserve 1034 bytes in memory5. T/F - In a two pass assembler, adding literals to literal table and address resolution of local symbol are done using first pass and second pass respectively.