If a steel column with cross-sectional area A = 1000 mm2, modulus of elasticity E 200 MPa and length of 10 m is subjected to 2 kN axial tension, compute for its axial deformation O + 100 mm O +0.1 mm O - 100 mm O - 1.0 m
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- A steel bar of length 30 m and having specific weight of 20 x 10-5 N/mm³. Find the elongation of the bar due to self weight (in mm, round off to two decimal places). (Assume modulus of rigidity of the material is 0.9 x 105 N/mm2 and poisson's ratio is 0.25)} 8) A tensile load of 3000 N is applied to a steel bar of cross-sectional area 500 mm?. If a tensile load was applied to an aluminum bar to achieve the same lateral (transvers) strain with the former (steel bar), what would be the load? Note: Original dimensions of the two bars are the same (Est = 2.1 x 105 MPa, Eat = 0.703 × 105 MPa, vg = 0.3, vat = 0.33) E = º , v = - Saterat Eaxial Fatuminum™ 3000 N A-500 mm² A=500 mm² Fatuminum=? 3000 N Steel Aluminum(40 How A Rismatic steel bar of a Square cro ss section (looxlo0)mm is loaoled by Compressive force P= 1300 K, the bar has length 2.5 m, Eg=200GPay V=0.3,determine the shortening 8, the increase in the dimensions of cross Section, the change in Volume DV of the bar? loomm loomm
- A steel column has the following properties: Modulus of elasticity, E = 200 GPa, yield strength, Fy = 200 MPa, length, L = 12 m, moment of inertia, I = 37.7 x 10° mm* and area = 9,000 mm². Determine the following compressive stress if the column is fixed at both ends.Compute the value the shear modulus G of steel whose modulus of elasticity E is 200 GPa and poisson's ratio is 0.30.a. A round steel bar with an initial diameter of 20 mm and length of 2 m is placed in tension, supporting a load of 2000 kg. If the Young's modulus of the bar is 200 GPa what is the length of the bar when supporting the load (assuming it does not yield)? b. If the Poisson's ratio of the steel is 0.4, what will the diameter of the bar be when supporting the load?
- 2.) Answer the following: a.) a 22 ft long solid steel rod is subjected to a load of 15,000 lb. This load causes the rod to stretch 0.435 in. The modulus of elasticity of the steel is 30,000,000 psi. Determine the diameter of the rod. b.) A solid circular titanium control rod must support an axial tension force of 12,000 lb. Assume that the modulus of elasticity of the titanium in 16,500,000 psi. If the rod must elongate no further than 0.35 in. when the normal stress of the rod is 68,000 psi, determine the minimum rod diameter AND the maximum rod length.A metal bar of variable cross section as shown and length is subjected to 1000 kN of force. The sections are of 1 m long section is 10000 sq.mm and that of 500 mm long section is 5000 sq.mm. Assuming the elastic modulus of 200 GPa, the total elongation of the bar will be?IV. An Aluminum bar AD (see figure) has a cross-sectional area of 250 mm2 and is loaded by forces P1 = 7560 N, P2 = 5340 N, and P3 = 5780 N. The lengths of the segments of the bar are a = 1525 mm, b = 610 mm, and c = 910 mm. (a) Assuming that the modulus of elasticity is E = 72 GPa, calculate the change in length of the bar. Does the bar elongate or shorten? (b) By what amount P should the load P3 be increased so that the bar does not change in length when the three loads are applied? (c) If P3 remains at 5780 N, what revised cross-sectional area for segment AB will result in no change of length when all three loads are applied? A k a B₁ P₁ b C P₂ -P3
- If a steel column with cross-sectional area A = 1000 mm^2 modulus of elasticity E = 200 MPa and length of 10 m is subjected to 2 kN axial tension, compute for its axial deformationProperties: Rod 1 8F D = 40 mm d = 20 mm L = 1.3 meter E = 80 Gpa ROD 1 ROD 2 Rod 2 D = 80 mm d = 20 mm L = 1.0 meters E = 80 Gpa 3F 2. The composite rod shown in the figure is composed of three rods rigidly welded together. Applied forces in terms of "F" are exerted in different parts of the composite rod. Compute the maximum safest value of "F" if the allowable total deformation of the composite rod is limited to 0.50 mm only. ROD 3 2F Rod 3 D = 60 mm d = 20 mm L = 1.2 meters E = 80 GPa 7FConsider a 1 m-long bar of 2024-T81 aluminum alloy with a 20mm-diameter and the following property data: E=70GPa Y.S.=410MPa T.S.=480MPa %Elongation at failure=8% What will be the length of the bar under a structural load of 1.2×10^5N in tension? Your answer should be in units of meters (m).