If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield,  what is the actual yield(grams )of sodium phosphate will be formed?     (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol                       Sn3(PO4)4 + 6 Na2CO3       →     3 Sn(CO3)2 + 4 Na3PO4

Chemistry for Engineering Students
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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.24PAE: 4.24 Ammonia gas can be prepared by the reaction CaO(s)+2NH4Cl(s)2NH3(g)+H2O(g)+CaCl2(s) If 112 g of...
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If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield,  what is the actual yield(grams )of sodium phosphate will be formed?     (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol

                      Sn3(PO4)4 + 6 Na2CO3       →     3 Sn(CO3)2 + 4 Na3PO4

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If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield,  what is the actual yield(grams )of sodium phosphate will be formed?     (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol

                      Sn3(PO4)4 + 6 Na2CO3       →     3 Sn(CO3)2 + 4 Na3PO4

note please explain well, I asked this already and it lacks info for me. 

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