If 465 g of Pb(NO3)2 (FW 331.21 g/mol) is added to a solution containing 215 g of K3PO4 (FW 212.27 g/mol), what mass, in g, of Pb3(PO4)2 (FW 811.54 g/mol) precipitate will be formed? The balanced equation is 3 Pb(NO3)2(aq) + 2 K3PO4(aq) → Pb3(PO4)2(S) + 6 KNO3(aq)

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
Problem 62QAP: Ten mL of concentrated H3PO4 (91.7% by mass, d=1.69g/mL) was accidentally poured into a beaker...
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If 465 g of Pb(NO3)2 (FW 331.21 g/mol) is added to a solution
containing 215 g of K3PO4 (FW 212.27 g/mol), what mass, in g, of
Pb3(PO4)2 (FW 811.54 g/mol) precipitate will be formed? The
balanced equation is
3 Pb(NO3)2(aq) + 2 K3PO4(aq) → Pb3(PO4)2(S) + 6 KNO3(aq)
Transcribed Image Text:If 465 g of Pb(NO3)2 (FW 331.21 g/mol) is added to a solution containing 215 g of K3PO4 (FW 212.27 g/mol), what mass, in g, of Pb3(PO4)2 (FW 811.54 g/mol) precipitate will be formed? The balanced equation is 3 Pb(NO3)2(aq) + 2 K3PO4(aq) → Pb3(PO4)2(S) + 6 KNO3(aq)
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