If 287.9 umol of enzyme X has a Vmax = 47.8 mmol/sec, what is the value of kcat sec-1? Please report answer with 1 decimal place. Please do not report units. Your Answer:

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Q: Calculate kcat for an enzyme where Vmax is 12 U s. mL and the total enzyme concentration is 0.016 U…

A: Given Values: Vmax = 12 u s-1ml-1 Total enzyme concentration = 0.016 U ml-1

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Q: Substrate Concentration (mol L1) Velocity (mM min-1) 2.500 0.588 1.000 0.500 0.714 0.417…

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Q: Vmax and Km were calculated for enzyme substrate data. Results Y=0,0063x+0,3929 Km =62,4 mikromol/L…

A: From the LB plot of enzyme kinetics, y=mx+c  It's an equation of a straight line. 1/V=(Km/Vm )1/S…

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Q: If a michaelis-type enzyme has an apparent Km of 2*10^-8 and apparent Vmax of 1*10^-4 moles/min in…

A: Uncompetitive inhibitors bind only to the enzyme–substrate complex and reduce both kcat and Km (the…

Q: Why can’t an enzyme have a kcat/KM value greater than 109 M−1 ∙ s−1?

A: Kcat/Km  is a measure of how many bound substrate molecules turnover or form product in 1 second.…

Q: The following data were obtained for a reaction that catalyzed by an enzyme: Initial concentration…

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A: Hi! Thank you for the question, as per the honor code, we are allowed to answer the first…

Q: An amylase result is 550 U/L. A 1:4 dilution is made and reads 180 U/L. What is the reported result?

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Q: Vmax [S] Km + [S] Vo = Eadie-Hofstee plot V v=Vm-Km [S] Lineweaver-Burk (L-B) plot 1 1 Km 1 Vm Vm…

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Q: If you multiplied enzyme concentration by kcat, think about what you would get. Which one of the…

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Q: concentration of each enzyme and with [X] = 1 µM. Which curve corresponds to which enzyme? Explain.

A: Given,  the substrate concentration is [X] =1 μM Km of enzyme A = 2.0 μM Km of enzyme B = 0.5 μM

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Q: [S] (MM) 0.5 1.0 1.5 Vo No Inhibitor (mM min-¹) Vo With Inhibitor (mM min¹¹) 16.67 25.25 30.49 23.5…

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Q: -8 K, for HCO3 ` = 2.38 × 10 Calculate Ka for the conjugate acid ( H¿CO;) For the reaction :…

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Q: Given the Km and Vmax values of three enzymes, A, B and C: Enzyme Km Vmax A 2.0 x 103 M 4.0 B 4.2 x…

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Q: Given the following values following processes can tak Thermodynamics?

A: A reaction is feasible when the change in free energy is negative here ∆G = ∆H-T∆SSo here when ∆H =…

Q: Consider the following reaction: Glucose-1-phosphate → Glucose-6-phosphate ΔG° = −7.1 kJ/mol What is…

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Q: For the following calculations, please provide your answers in whole numbers (no decimals). A…

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Q: The ΔG°′ value for glucose-1-phosphate is -20.9 kJ/mol. If glucose and phosphate are both at 4.8 mM,…

A: Given values: ∆G° = -29.9 kJ/mol [Glucose] = 4.8 mM [phosphate] = 4.8 mM [Glucose-1-phosphate] = ?…

Q: An attempt was made to inhibit Enzyme X by adding compounds M and L. The results are summarized in…

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Q: Determine the values of KM and Vmax for the decar- boxylation of a β-keto acid given the following…

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Q: What are the meanings and differences between Ki, Km, and IC50? Are there certain advantages or…

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Q: What are the optimal conditions for an enzyme(full answer)?

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

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Q: A Lineweaver-Burk Plot is shown below. 30 Curve A y = 3.1207x + 2.4978 20 15 Curve B y = 1.0003x +…

A: Lineweaver-Burk plot is a graphical representation used in enzymology. It can be used in the absence…

Q: In an enzyme kinetics study, three inhibitors resulted to the following results: Inhibitor ABC…

A: Vmax km Competitive   remains same increases Non Competitive  Decreases remains same…

Q: 1/V, min/umol 5.50 5.00 4.50 4.00 3.50 answer. 3.00 2.50 2.00 0.00 y = 0.9474x + 2.6649 0.50 1.00…

A: Double reciprocal plot is also called as lb plot that is drawn by taking inverse of Substrate…

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Q: The conversion of glucose-1-phosphate to glucose-6-phosphate by the enzyme phosphoglucomutase has a…

A: According to standard free energy change ∆G0 = -RT ln Keq where ∆G0 =standard free energy change…

Q: Calculate the overall ΔG° (report up to two decimal places) for the net reaction (see attached…

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