If 20 mL of a hydrochloric acid solution (HCl) required 18 mL of a sodium hydroxide in a titration and 35mL of the said base is equivalent to 0.8323 g of potassium bipthalate (KHC8H4O4), what would be the normality of the HCl solution? Atomic Weights : Sodium - 22.99 Oxygen - 15.999 Hydrogen - 1.008 Potassium - 39.098 Chlorine - 35.45 Enter numerical value only; round off to 4 decimal places

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Chapter7: Solutions And Colloids
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Problem 7.107E
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If 20 mL of a hydrochloric acid solution (HCl) required 18 mL of a sodium hydroxide in a titration and 35mL of the said base is equivalent to 0.8323 g of potassium bipthalate (KHC8H4O4), what would be the normality of the HCl solution?

Atomic Weights :
Sodium - 22.99
Oxygen - 15.999
Hydrogen - 1.008
Potassium - 39.098
Chlorine - 35.45

Enter numerical value only; round off to 4 decimal places

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