If 136 g of BaCl₂ (FW 208.23 g/mol) is added to a solution containing 95.0 g of Na3PO4 (FW 163.94 g/mol), what mass, in g, of Ba3(PO4)2 (FW 601.92 g/mol) precipitate will be formed? The balanced equation is 3 BaCl₂(aq) + 2 Na3PO4(aq) →→ Ba3(PO4)2(s) + 6 NaCl(aq) ->>>

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Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.160QP: Determine the volume of sodium hydroxide solution needed to prepare 26.2 g sodium phosphate, Na3PO4,...
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If 136 g of BaCl₂ (FW 208.23 g/mol) is added to a solution containing
95.0 g of Na3PO4 (FW 163.94 g/mol), what mass, in g, of Ba3(PO4)2
(FW 601.92 g/mol) precipitate will be formed? The balanced equation
is
3 BaCl₂(aq) + 2 Na3PO4(aq) → Ba3(PO4)2(S) + 6 NaCl(aq)
Transcribed Image Text:If 136 g of BaCl₂ (FW 208.23 g/mol) is added to a solution containing 95.0 g of Na3PO4 (FW 163.94 g/mol), what mass, in g, of Ba3(PO4)2 (FW 601.92 g/mol) precipitate will be formed? The balanced equation is 3 BaCl₂(aq) + 2 Na3PO4(aq) → Ba3(PO4)2(S) + 6 NaCl(aq)
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