Identify the material that has maximum stiffness value from the following stress- strain curves.
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- Sketch a representative stress-strain digrama for a ductile material showing the following on it (label the axis and provid units). 1- YIELD STRENGTH. 2- TENSILE STRENGTH. 3- FRACTURE POINT. 4- HARDENING PART. 5- SOFTENING PART. 6- A METHOD TO CALCULATE THE STIFFNESS. 7- A METHOD TO CALCULATE THE DUCTILITY.Tensile test specimens are extracted from the "X" and "y" directions of a rolled sheet of metal. "x" is the rolling direction, "y" is transverse to the rolling direction, and "z" is in the thickness direction. Both specimens were pulled to a longitudinal strain = 0.15 strain. For the sample in the x-direction, the width strain was measured to be ew= -0.0923 at that instant. For the sample in the y-direction, the width strain was measured to be gw=-0.1000 at that instant. The yield strength of the x-direction specimen was 50 kpsi and the yield strength of the y-direction specimen was 52 kpsi. Determine the strain ratio for the x direction tensile test specimen. Determine the strain ratio for the y-direction tensile test specimen. Determine the expected yield strength in the z-direction. Give your answer in units of kpsi (just the number). If the sheet is plastically deformed in equal biaxial tension (a, = 0, to the point where & = 0.15, calculate the strain, 6, that would be expected.Bronze alloy, the following true stresses produce the corresponding plastic true strains, before to necking: On the basis of this information, compute the true stress necessary to produce a true strain of 0.25 and then find the engineering stress and strain at this point. True stresses (MPa) True strain 354 0121 70 018
- Stress Strain Diagram The Data shown in the table have been obtained from a tensile test conducted on a high-strength steel. The test specimen had a diameter of 0.505 inch and a gage length of 2.00 inch. Using software. plot the Stress-Strain Diagram for this steel and determine its: A= TTdT(050s A %3D 1. Proportional Limit, 2. Modulus of Elasticity, 3. Yield Strength (SY) at 0.2% Offset, 4. Ultimate Strength (Su), 5. Percent Elongation in 2.00 inch, 6. Percent Reduction in Area, 7. Present the results (for Steps 1-6) in a highly organized table. e Altac ie sheet (as problelle 4 A = 0.2.002 BEOINNING of the effort Elongation (in) Elongation (In) Load Load #: #3 (Ib) (Ib) 1 0.0170 15 12,300 0.0004 1,500 16 12,200 0.0200 0.0010 3. 3,100 17 12,000 0.0275 0.0016 4,700 18 13,000 0.0335 5. 6,300 0.0022 19 15,000 0.0400 0.0026 6. 8,000 20 16,200 0.055 0.0032 9,500 21 17,500 0.0680 0.0035 8. 11,000 22 18,800 0.1080 0.0041 11,800 23 19,600 0.1515 0.0051 24 20,100 0.2010 10 12,300 0.0071 25…Example: Convert the change in length data in Table 3-2 to engineering stress and strain and plot a stress-strain curve Homework- help Table 3-2 The results of a tensile test of a 0.505 in. diameter aluminum alloy test bar, initial length (1o) = 2 in. Calculated LTO Load (Ib) Change in Length (in.) Stress (psi) Strain (in./in.) 0.000 1000 0.001 0.0005 4,993 14,978 24,963 34,948 37,445 39,442 39,941 39,691 37,944 3000 0.003 0.0015 5000 0.005 0.0025 7000 0.007 0.0035 7500 0.030 0.0150 7900 0.080 0.0400 8000 (maximum load) 0.120 0.0600 7950 0.160 0.0800 7600 (fracture) 0.205 0.1025200 stress 150 (MPa) 100 50 0-2 strain From the tensile stress-strain behavior for the brass specimen cP the diameter is 12-8 mm Calculate the folwing:- 1- The Yield stress, 2-Modulus of elasticity. 3- The Tensile strength .
- In stress and strain diagram for a perfectly ductile material, the yield strength, and ultimate tensile strength are well defined Select one: O True O FalseUse the engineering stress strain diagram provided below to answer parts (A) to (H) below (the stress-strain diagram bas already been drawn for you): stress strain diagram 400 350 0 300 0 250 0 200 0 150.0 100.0 50.0 O 05 0 1 0.15 strain A. Determine the tensile strength of this alloy. B. show the elastic, plastic and total strain on the diagram stress (Mpa)Gerilme-Şekil Değiştirme Diyagramı = Stress-Strain Diagram
- 2) Use the engineering stress strain diagram provided below to answer parts (A) to (H) below (the stress-strain diagram has already been drawn for you): stress strain diagram 400 350 0 300 0 250 0 200 0 150.0 100.0 50.0 00 0 05 01 0. 15 strain A. Determine the tensile strength of this alloy. B. show the clastic, plastic and total strain on the diagram stress (Mpa)After explaining the difference between the true stress/strain and the nominal stress/strain, show the true stress-strain diagram for the nominal stress-strain diagram (Figure 1) to correspond points 1, 2, 3, and 4.Problem F2 stress (ksi) 130 120 110 100 90 80 70 60 50 40 30 20 10 0 0.000 0.025 0.050 0.075 0.100 0.125 0.150 0.175 strain (in/in) Above you will find the experimental stress-strain diagram of 1045 steel. Calculate the permanent set if a cylindrical specimen with a diameter of 2 in is loaded to the ultimate stress and then unloaded. Provide your answer in units of in/in with 3 significant figures after the decimal. The elastic modulus of 1045 steel is 29,000 ksi.