How much work does it take to move an electron 7.0 m at an angle of 30.0° to the x-axis, in the presence of a uniform electric field E = 5.0 N/C in the x-axis?
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A: q1 = 5.40 nC q2 = -5.40 nCq3 = 3.30 nC
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Q: How much work is required to turn an electric dipole 180° in a uniform electric field of magnitude…
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A: Given: Charge Q=3 μC Charge = q, Work done to bring them closer = 29 J
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- aA plastic rod of length = 24.0 cm is uniformly charged with a total charge of +12.0 C. The rod is formed into a semicircle with its center at the origin of the xy plane (Fig. P24.34). What are the magnitude and direction of the electric field at the origin? Figure P24.34Two solid spheres, both of radius 5 cm, carry identical total charges of 2 C. Sphere A is a good conductor. Sphere B is an insulator, and its charge is distributed uniformly throughout its volume. (i) How do the magnitudes of the electric fields they separately create at a radial distance of 6 cm compare? (a) EA EB = 0 (b) EA EB 0 (c) EA = EB 0 (d) 0 EA EB (e) 0 = EA EB (ii) How do the magnitudes of the electric fields they separately create at radius 4 cm compare? Choose from the same possibilities as in part (i).A cylindrical distribution of charge ρ = α /√ r where α = 2 µC/m 5/2 extends from 0 cm to 9.3 cm . Concentric with this is a dielectric shell with 5.44 of inner radius 16.6 cm and outer radius 24.9 cm . What is the electric field at 3.53 cm ?
- How much work is required to turn an electric dipole 180o in a uniform electric field of magnitude 44.2 N/C if p = 3.20 × 10-25 C·m and the initial angle is 16.7o.An electron is released from rest at a distance of 0.300 m from a large insulating sheet of charge that has uniform surface charge density +2.90 * 10-12 C/m2. (a) How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 0.050 m from the sheet? (b) What is the speed of the electron when it is 0.050 m from the sheet?Two horizontal metal plates, each 100 mm square, are aligned 10.0 mm apart, with one above the other. They are given equal-magnitude charges of opposite sign so that a uniform downward electric field of 2 000 N/C exists in the region between them. A particle of mass 2.00 x 10-16 kg and with a positive charge of 1.00 x 10-6 C leaves the center of the bottom negative plate with an initial speed of 1.00 x 105 m/s at an angle of 37.0° above the horizontal. Describe the trajectory of the particle. Which plate does it strike? Where does it strike, relative to its starting point?
- A proton is projected in the positive x direction into a region of a uniform electric field E= -3.00 * 10° i N/C at t = 0. The proton travels 6.00 cm before coming to rest. Determine its initial speed? (proton mass 1.6 * 1027 kg)A metal sphere of radius 5.00 cm is initially uncharged. How many electrons would have to be placed on the sphere to produce an electric field of magnitude 1.43 x 10° N/C at a point 8.60 cm from the center of the sphere? electronsHow much work is required to turn an electric dipole 180° in a uniform electric field of magnitude 44.0 N/C if p = 3.82 × 1025 C-m and the initial %3D angle is 22.3°.
- In figure 2, an upwardly oriented uniform electric field E⃗ of a magnitude of 2.0 × 103 N / C has been established between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have a length L = 10.0 cm, and they are at a distance of d = 2.0 cm. An electron is sent between the plates from the left end of the lower plate. The initial velocity ⃗v0 of the electron forms an angle θ = 45◦ with the lower plate, and its magnitude is 6.0 × 106 m / s (a) Will the electron touch one of the plates? (b) If so, determine which one. Then find how far horizontally from the left end the electron will strike.When the nucleus of uranium-235 (92 protons and 143 neutrons) absorbs an additional neutron, it undergoes a process called nuclear fission in which it breaks into two smaller nuclei. One possible fission is for uranium nucleus to divide into two palladium nuclei, each of which has 46 protons and 5.9 x 10−15 m in radius. The palladium nuclei then fly apart (their separation if essentially infinite) due to their electric repulsion. If (immediately after the fission) we assume that the palladium nuclei are at rest and are just touching each other, what is their combined kinetic energy when they are very far apart? [Hint: Use the conservation of mechanical energy equation.]What is the work required to rotate an electric dipole by 180º in a uniform electric field of modulus E = 46.0 N / C if p = 3.02 × 10-25C ∙ m and the initial angle is 64º?