1. Calculate the number of moles of He atoms present in 4.89 g of He. 2. 7:06STARTING AMOUNTHow many moles of propylene (C3H₁) are in 25.0of the substance?ADD FACTORXx( )1.0114.15 x 10-2312.0136.030.6940.59425.06.022 x 10²3Question 7 of 1042.09molecules C3H6mol C3H6Xg C3H6/molg C3H6ANSWER=.5GETap here or pull up for additional resourcesSubmitgRESET3

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How many moles of propylene (C3H) are in 25.0 of the substance? g

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter3: Stoichiometry

Section: Chapter Questions

Problem 55E: What amount (moles) of compound is present in 1.00 g of each of the compounds in Exercise 51?

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

1. Calculate the number of moles of He atoms present in 4.89 g of He.

7:06
STARTING AMOUNT
How many moles of propylene (C3H₁) are in 25.0
of the substance?
ADD FACTOR
X
x( )
1.01
1
4.15 x 10-23
12.01
36.03
0.694
0.594
25.0
6.022 x 10²3
Question 7 of 10
42.09
molecules C3H6
mol C3H6
X
g C3H6/mol
g C3H6
ANSWER
=
.5GE
Tap here or pull up for additional resources
Submit
g
RESET
3

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