How many mL of 0.535 M HI are needed to dissolve 7.98 g of BaCO3?2HI(aq) + BaCO3(s) →→→→→→ BaI₂(aq) + H₂O(1) + CO₂(g)mL For the following reaction, 18.0 grams of chlorine gas are allowed to react with 3.70 grams of water.chlorine (g) + water (1) →→→→→→→ hydrochloric acid ( aq ) + chloric acid (HCIO3) ( aq )What is the maximum amount of hydrochloric acid that can be formed?What is the FORMULA for the limiting reagent?What amount of the excess reagent remains after the reaction is complete?gramsgrams

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How many mL of 0.535 M HI are needed to dissolve 7.98 g of BaCO3? 2HI(aq) + BaCO3(s) BaIz(aq) + H2O(I) + CO2(g) mL

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter21: The Chemistry Of The Main Group Elements

Section21.5: The Alkaline Earth Elements, Group 2a

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Question

How many mL of 0.535 M HI are needed to dissolve 7.98 g of BaCO3?
2HI(aq) + BaCO3(s) →→→→→→ BaI₂(aq) + H₂O(1) + CO₂(g)
mL

For the following reaction, 18.0 grams of chlorine gas are allowed to react with 3.70 grams of water.
chlorine (g) + water (1) →→→→→→→ hydrochloric acid ( aq ) + chloric acid (HCIO3) ( aq )
What is the maximum amount of hydrochloric acid that can be formed?
What is the FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete?
grams
grams

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