How many grams of NBr3 can be made from 525 g Br2  ?  N2   +   3 Br2   →   2 NBr3   +   44.0 kJ              The molar mass of NBr3 is 253.719 g and the molar mass of Br2 is 159.808 g                    ________________  mol Br2                                                                                       (525 g Br2)(–––––––––––––––––––––––––––)  = _____________ mol Br2                    _________________  g Br2                                                                                                                                                             _________________ mol NBr3     _____________________ mol Br2 (–––––––––––––––––––––––––––––––) =  ______________ mol NBr3                                                            _________________ mol Br2

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter4: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 20Q: A student wants to prepare 1.00 L of a 1.00-M solution of NaOH (molar mass = 40.00 g/mol). If solid...
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How many grams of NBr3 can be made from 525 g Br2  ?

 N2   +   3 Br2   →   2 NBr3   +   44.0 kJ             

The molar mass of NBr3 is 253.719 g and the molar mass of Br2 is 159.808 g

                   ________________  mol Br2                                                                                      

(525 g Br2)(–––––––––––––––––––––––––––)  = _____________ mol Br2

                   _________________  g Br2

                                                                                                 

                                                          _________________ mol NBr3   

 _____________________ mol Br2 (–––––––––––––––––––––––––––––––) =  ______________ mol NBr3

                                                           _________________ mol Br2 

 

                                                           __________  g NBr3

 __________________ mol NBr3 (–––––––––––––––––––––––––––––) = _____________ g NBr3      note:  this is a theoretical yield

                                                         ______________ mol NBr3

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