How many energetically different eclipsed conformations does 1-bromo-2-methylpropane, viewed along the C1- C2 bond, have?To be able to answer the question, draw and analyze the Newman projections for the different conformations.

The Newmann projections are stable when two bulky groups or atoms have a decent separation between…

Answered: How many energetically different…

How many energetically different eclipsed conformations does 1-bromo-2-methylpropane, viewed along the C1- C2 bond, have?|

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter6: Alkanes & Alkenes

Section: Chapter Questions

Problem 4E: Consider the molecule 1-bromo-2-methylbutane. C3 and C4 should be drawn as Et as in theexample. This...

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Concept explainers

Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.

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How many energetically different eclipsed conformations does 1-bromo-2-methylpropane, viewed along the C1- C2 bond, have?
To be able to answer the question, draw and analyze the Newman projections for the different conformations.

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I don't understand why the first one and second one are cis and trans respectively. Wouldn't the first one be trans-1,2-dimethylcyclobutane because the torsional strain wouldn't allow the carbons to be in the same conformation. Meaning one of the carbons would be up and then the next would be down and so on. Since both methyl groups are equatorial and the first and second carbons are arranged up and down, wouldn't it be trans. Same logic for the second molecule. Carbon 1, which is attached to the methyl is down, carbon 3 which is attached to the methyl should be down also because of torsional strain, and since both methyl are in axial (or equatorial?), it would be cis. Or is it based off of the way the carbons are positioned in the picture?
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