Here for this questions 1st part how did you take n's value as 1.305 ? As in the question its not mentioned . Please explain..

Introductory Circuit Analysis (13th Edition)
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Here for this questions 1st part how did you take n's value as 1.305 ? As in the question its not mentioned . Please explain..
3. ) Estimate the optical loss due to Fresnel reflection at a fiber core from GaAs
each of refractive indices 1.48 and 3.5 respectively.
b) Calculate the optical power emitted into air for the device, when the step
index fiber has a numerical aperture of 0.16, coupled power of 0.31 mW.
c) Determine the overall power conversion efficiency for the LED if it is
operating with a drive current of 210 mA and a forward voltage of 1.5V.
d) Find the optical output power at 170MHZ, and calculate the optical and
electrical modulation bandwidth for a minority carrier recombination life time
of 9ns.
Transcribed Image Text:3. ) Estimate the optical loss due to Fresnel reflection at a fiber core from GaAs each of refractive indices 1.48 and 3.5 respectively. b) Calculate the optical power emitted into air for the device, when the step index fiber has a numerical aperture of 0.16, coupled power of 0.31 mW. c) Determine the overall power conversion efficiency for the LED if it is operating with a drive current of 210 mA and a forward voltage of 1.5V. d) Find the optical output power at 170MHZ, and calculate the optical and electrical modulation bandwidth for a minority carrier recombination life time of 9ns.
Since this question contains multiple
parts , also rest of the part are not
cleary visible except the first , please
post the remaining question again , i
am solving the part 1
Write the expression for Fresnel reflection of source to gel.
n, -n
R =
n, +n
Here,
n, = Refractive index of the source
n= Refractive index of the gel
Substitute 3.6 for n, and 1.305 for n
Step2
b)
R s-g = (1.48 - 1.305 / 1.48 + 1.305)²
Rs-g = 3.94*10-3
Write the expression for Fresnel reflection of source to gel.
n, -n
Rg-f
n, +n
Transcribed Image Text:Since this question contains multiple parts , also rest of the part are not cleary visible except the first , please post the remaining question again , i am solving the part 1 Write the expression for Fresnel reflection of source to gel. n, -n R = n, +n Here, n, = Refractive index of the source n= Refractive index of the gel Substitute 3.6 for n, and 1.305 for n Step2 b) R s-g = (1.48 - 1.305 / 1.48 + 1.305)² Rs-g = 3.94*10-3 Write the expression for Fresnel reflection of source to gel. n, -n Rg-f n, +n
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