Heptane (C7H16)(C7H16) is a component of gasoline that burns according to the following balanced equation: C7H16(l)+11O2(g)→7CO2(g)+8H2O(g)C7H16(l)+11O2(g)→7CO2(g)+8H2O(g)   Calculate ΔrH∘ΔrH∘ for this reaction using standard enthalpies of formation. (The standard enthalpy of formation of liquid heptane is -224.4 kJmol−1kJmol−1, of gaseous carbon dioxide is −−393.5 kJmol−1kJmol−1, and of gaseous water is −−241.8 kJmol−1kJmol−1.)

Chemistry & Chemical Reactivity
10th Edition
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 69GQ: Use Appendix L to find the standard enthalpies of formation of oxygen atoms, oxygen molecules (O2),...
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Heptane (C7H16)(C7H16) is a component of gasoline that burns according to the following balanced equation:

C7H16(l)+11O2(g)→7CO2(g)+8H2O(g)C7H16(l)+11O2(g)→7CO2(g)+8H2O(g)

 
Calculate ΔrH∘ΔrH∘ for this reaction using standard enthalpies of formation. (The standard enthalpy of formation of liquid heptane is -224.4 kJmol−1kJmol−1, of gaseous carbon dioxide is −−393.5 kJmol−1kJmol−1, and of gaseous water is −−241.8 kJmol−1kJmol−1.)
Express your answer in kilojoules per mole to one decimal place.
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