he dots in the graph below show the absolute errors of replicate results obtained by four analysts. -2.0 Analyst 4 Analyst 1 Analyst 3 Analyst 2 (x₂-x1). -1.5 -(x4-Xt) (1 − XD) -1.0 (x₂-x1). -0.5 0 Absolute error (x; -x₂), %N etermine which 2 analysts have significantly fewer random errors as compared to the remaining 2 analysts. SOS CSSSS Analyst 1 Benzyl isothiourea hydrochloride Analyst 2 Benzyl isothiourea hydrochloride Analyst 3 Nicotinic acid Analyst 4 Nicotinic acid 0.5 1.0

he dots in the graph below show the absolute errors of replicate results obtained by four analysts. -2.0 Analyst 4 Analyst 1 Analyst 3 Analyst 2 (x₂-x1). -1.5 -(x4-Xt) (1 − XD) -1.0 (x₂-x1). -0.5 0 Absolute error (x; -x₂), %N etermine which 2 analysts have significantly fewer random errors as compared to the remaining 2 analysts. SOS CSSSS Analyst 1 Benzyl isothiourea hydrochloride Analyst 2 Benzyl isothiourea hydrochloride Analyst 3 Nicotinic acid Analyst 4 Nicotinic acid 0.5 1.0

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.27QAP

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2) As an example of precision and accuracy of data, suppose the % carbon in a single compound has been measured thrce separate times by 2 different students. The theoretical % carbon is 21.34%. Student 1: trial 1:26.11%, trial 2: 26.24% trial 3: 25.92 %, Avg - 26.09 Student 2: trial 1: 20.35%. trial 2: 22.64 % trial 3: 19.79 %. Avg = 20.93 a) Which student had the more precise data and how can you tell? b) Which student had the more accurate data and how can you tell? 3a) Calculate the % error of Student 1 data in problem 2 above. Show all work below. WATCH SIG FIGS
The dots in the graph below show the absolute errors of replicate results obtained by four analysts. -2.0 -1.5 O Analyst 1 Analyst 3 Analyst 4 (3 - XĐ). O Analyst 2 } (X) -1.0 (1-XĐ) (2-x)) -0.5 0 Absolute error (x; -x₂), %N Analyst 1 Benzyl isothiourea hydrochloride Analyst 2 Benzyl isothiourea hydrochloride Analyst 3 Nicotinic acid Determine which 2 analysts have significantly fewer systematic errors as compared to the remaining 2 analysts. Analyst 4 Nicotinic acid 0.5 1.0
EXAMPLE Significant Figures in Laboratory Work You prepared a 0.250 M NH, solution by diluting 8.46 (0.04) mL of 28.0 (10.5) wt% NH, [density=0.899 (+0.003) g/mL] up to 500.0 (+0.2) mL. Find the uncertainty in 0.250 M. The molecular mass of NH3, 17.031 g/mol, has negligible uncertainty relative to other uncertainties in this problem.
The percentage of an additive in gasoline was measured six times with the following results: 0.13; 0.12; 0.16; 0.17; 0.20 and 0.11%. What is the 99% confidence interval for the additive percentage?
Teacher's Aixtre 09 7. Mass of dry filter paper + benzoic acid 1315 8. Mass of recovered benzoic acid 315 2.9128-1D0128 Calculations Percent sand:.&oy 1o0 40.32 inen tel valne Percent benzoic acid: O.101 X100=10.O47 1. Calculate the percent of each component in the mixture. Show your calculations. 3.978 3.978 Percent NaCl: 100 2. Obtain the percent composition of the teacher's mixture. Calculate the percent error in your results. Show your calculations. JyoisSand % error: 40%-40.3al x100= 0.8 7 니0 a0Benzoic acid % error: NaCl % error: Analysis in the class received a sample of the same mixture, each team will not obtain th of reasons (hint: read the
Propagate the error in the following expression:(0.5847(±0.0002)mole / 250.0(0.1)??) ×(1000 ml / 1 L)
Which of the following is NỘT an equivalent expression for the confidence interval given by 161.7
Analysis was run on samples from a known CRM with 8.85% Fe. The following results for %Fe were obtained by an analyst: 8.75, 8.51, 8.25, 8.61. Which of the following statements is true assuming none of the data points are outliers? Group of answer choices Tcalc = 63.15 The analysis is not accurate at the 95% confidence interval. Tcalc = 3.03 The analysis is accurate at the 95% confidence interval. Not enough information to determine Tcalc = 63.15 The analysis is accurate at the 95% confidence interval. Tcalc = 3.03 The analysis is not accurate at the 95% confidence interval.
Mla pnc.com/women Mail - Whi x O Grades for x Course Ho X G oxide cont X G Exercise 4.x E 4 - Molecu x O Bananas a X 1.84 x 10- x + envellum.ecollege.com/course.html?courseld 16985674&OpenVellumHMAC=a0b841caaee7feddab1623a6c83a92c0#10001 Review | Constants I Periodic Table Percent composition refers to the mass percent of each element in a compound: mass of element Part A mass percent = x 100% mass of compound > For example, the percent composition of water, H2O. is 11.2% hydrogen and 88.8% oxygen. Therefore, a 100-g sample of water contains 11.2 g of hydrogen atoms and 88.8 g of oxygen atoms. A hydrocarbon is a compound that contains mostly carbon and hydrogen. Calculate the percent composition (by mass) of the following hydrocarbon: CH22 Enter the percentages of carbon and hydrogen numerically to four significant figures, separated by commas. The periodic table will be useful when doing this problem. You can access a periodic table by clicking the "Tools" link in the upper right…
Example 2: You prepared a 0.250 M NH3 solution by diluting 8.45 (±0.04) mL of 28.0 (10.5) wt% NH3 [density = 0.899 (+0.003) g/mL] up to 500.0 (±0.2) mL. Find the uncertainty in 0.250 M. The molecular mass of NH3, 17.0306 g/mol, has negligible uncertainty relative to other uncertainties in this problem.
3. For 100 firms on NYSE, we know: X=sector of activity (finance, tourism, statistics) and Y=return on stocks (0-5:5-10;10-15). On average, the return of a company from finance sector is 12.5. On average, the return of a company from tourism sector is 12.5. On average, the return of a company from statistics sector is 12.5. Which of the following statements is true in regards the relationship between X and Y? Select one: O a. low correlation O b. strong correlation OC. medium-intensity correlation O d. No correlation
1. (40 pts) We can measure the concentration of HCl solution by reaction with pure sodium carbonate: 2H + Na2CO3 →2Na+ + H₂O + CO₂ Complete reaction with 0.9674 +0.0009 g of Na2CO3 (FM 105.9884 +0.0007) required 27.35 0.04 mL of HCl. Find the molarity of the HCI and its absolute uncertainty.