HAMMA A steel bar 100 mm long is subjected to a tensile stress o. If change in length of bar is 0.05 mm what is the value of o? Given E = 200 GPa
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- The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.q7 A steel bar 2 m long, 20 mm wide and 15 mm thick is subjected to a tensile load of 30 kN. If Poisson's ratio is 0.25 and Young's modulus is 200 GPa, an increase in volume will be (b) 150 mm3 (d) 130 mm3 (a) 160 mm3 (c) 140 mm34. A 2.0 m steel is being subjected into a tensile test. At force 30 kN, the length of the steel is now 2.2 m, but after the force has been released, the steel returned to 2.1 m. The state of the steel is at?
- SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and attached to two vertical rods. Assume that the rods were initially stress-free. Allowable stress in steel is 120 MPa and in bronze is 60 MPa. For this problem, a = 1.8m; b = 1.3m; c= 1.7m. a b I Steel: A 900 mm Bronze: A E 200 GPa E 83 GPa L-2.0m L=1.5m What is the value of P without exceeding the allowable stress of steel, in KN? 230 250 280 340 1200 mmA mild steel bar of square cross-section 40 mm x 40 mm is 400 mm long it is subjected to a longitudinal tensile stress of 440 N/mm² and lateral compressive stress is 200 N/mm² in perpendicular directions. E = 2 x 105 N/mm², μ = 0.3. What is the approximate elongation of the bar in the longitudinal direction?A tapered steel bar of length 2m is subjected to an axial load of 20kN. Take modulus of steel as 200GPa. What is the strain produced in the bar? (in 10-5) = 100 mm 2m >= 50 mm 20000 N
- A steel rod with a cross sectional area of 120 (mm) ^2 is stretched between two fixed points. The tensile load at 20°C is 4200N. What will be the stress at-25°C? a=11.7x [10] ^(-6)/°C and E = 200GPA. See figure 06. * Figure 06 120 MPa 130 MPa 140 MPa 150 MPaA 30m long aluminum bar is subjected to a tensile stress of 172 MPa. Find the elongation in mm if E = 69,116 MPa.A hollow steel member has an inside diameter of 50mm,a wall thickness of 5mm,a length of 1500mm and a modulus of elasticity of 210GPa.if the member is subjected to a tensile load of 5KN, determine each of the following dimensional changes.(take Poisson's ratio to be 0.4) 1.elongation 2.change in thickness
- SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and attached to two vertical rods. Assume that the rods were initially stress-free. Allowable stress in steel is 120 MPa and in bronze is 60 MPa. For this problem, a = 1.8m; b = 1.3m; c= 1.7m. a b C P Steel: A-900 mm² Bronze: A=1200 mm² E = 83 GPa L=2.0 m E = 200 GPa L=1.5m What is the value of P without exceeding the allowable stress of bronze, in kN? O 161 O 174 O 145 124 4A steel section having a cross section of 20 mm x 30 mm is subjected to an axial force of 240 kN. The steel section has produces a strain of 0.002. If it has a value of Poisson's ratio of 0.30. Which of the following gives the bulk modulus of the steel section. a. 133333 MPa b. 166667 MPa c. 111111 MPa d. 144444 MPaIn the figure shown below, determine: 1) The final temperature if the normal stress at aluminium is Og = -90 MPa and the initial temperature %3D 20°C. 2) The final length of the aluminium member. Aluminum A=1800mm? Bronze A=1500mm? E=73GPA E=105GPA a=23.2x10-6/°C a=21.6x10-6/°C Gap=0.5mm 0.35m 0.45m