H2(g) + I2(g) → 2HI(g)I was given this problem:A student makes the following statements:Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H2 and product HI.Iodine is in Group VIIA, so it has an oxidation number of –1 in both the reactant I2 and product HI.Neither hydrogen nor iodine changes oxidation states, so the reaction is not a redox reaction.How can I describe the mistake that the student made, and determine whether or not the reaction is a redox reaction.

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Answered: H2(g) + I2(g) → 2HI(g) I was given…

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter13: Electrochemistry

Section: Chapter Questions

Problem 13.101PAE

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H₂(g) + I₂(g) → 2HI(g)

I was given this problem:

A student makes the following statements:

Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H₂ and product HI.
Iodine is in Group VIIA, so it has an oxidation number of –1 in both the reactant I₂ and product HI.
Neither hydrogen nor iodine changes oxidation states, so the reaction is not a redox reaction.

How can I describe the mistake that the student made, and determine whether or not the reaction is a redox reaction.

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