H.W.For the circuit in Figure below, calculate the low and high-criticalfrequency. Assumed re' = 9.6 and B = 200.fel = 282 Hz, fc3 = 50.8 Hz and fc2 =36 Hzfcu(in) =1.62MHZ and fcu(out) =60.3Mhz%3D%3D%3DVcc+15 VRe3.9 knR68 kNVutR,0.33 µFRL5.6 kN2N3904600 N0.1 µFREI33 2R222 kf250 mVppRp21.5 k2C2100 µF

Answered: Image /qna-images/answer/343bc38f-07c0-4428-98ce-af5f7b4090cb.jpg

Answered: H.W. For the circuit in Figure below,…

H.W. For the circuit in Figure below, calculate the low and high-critical frequency. Assumed re' = 9.6 and B = 200. fel = 282 Hz, fe3 = 50.8 Hz and fc2 =36 Hz feu(in) =1.62MHZ and fcu(out) =60.3Mhz

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

HVDC

HVDC stands for high voltage direct current in the electric power transmission system. The high voltage direct current system uses direct current (DC) for the transmission of electrical power through transmission lines in contrast with the alternating current that is the AC system. The HVDC is used to transmit bulk power point-to-point through long distances transmission lines. Power is rapidly transferred because the efficiency of transmission lines is greatly increased over long distances due to HVDC lines.

Question

H.W.
For the circuit in Figure below, calculate the low and high-critical
frequency. Assumed re' = 9.6 and B = 200.
fel = 282 Hz, fc3 = 50.8 Hz and fc2 =36 Hz
fcu(in) =1.62MHZ and fcu(out) =60.3Mhz
%3D
%3D
%3D
Vcc
+15 V
Re
3.9 kn
R
68 kN
Vut
R,
0.33 µF
RL
5.6 kN
2N3904
600 N
0.1 µF
REI
33 2
R2
22 kf2
50 mVpp
Rp2
1.5 k2
C2
100 µF

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