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Government regulations dictate that for any production process involving a certain toxic chemical, the water in the output of the process must not exceed 7640 parts per million (ppm) of the chemical. For a particular process of concern, the water sample was collected by a manufacturer 25 times randomly and the sample average x was 7666 ppm. It is known from historical data that the standard deviation σ is 130 ppm. Complete parts (a) and (b) below Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) What is the probability that the sample average in this experiment would exceed the government limit if the population mean is equal to the limit? Use the Central Limit Theorem. The probability is (Round to four decimal places as needed.) (b) Is an observed x=7666 in this experiment firm evidence that the population mean for the process exceeds the government limit? Answer your question by computing P (X≥ 7666 | µ = 7640). Assume that the distribution of the concentration is normal. Since P(X≥7666 | μ=7640) = [ the process exceeds the government limit. (Round to four decimal places as needed.) negligible, the observed x evidence that the population mean for is not is

Government regulations dictate that for any production process involving a certain toxic chemical, the water in the output of the process must not exceed 7640 parts per million (ppm) of the chemical. For a particular process of concern, the water sample was collected by a manufacturer 25 times randomly and the sample average x was 7666 ppm. It is known from historical data that the standard deviation σ is 130 ppm. Complete parts (a) and (b) below Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) What is the probability that the sample average in this experiment would exceed the government limit if the population mean is equal to the limit? Use the Central Limit Theorem. The probability is (Round to four decimal places as needed.) (b) Is an observed x=7666 in this experiment firm evidence that the population mean for the process exceeds the government limit? Answer your question by computing P (X≥ 7666 | µ = 7640). Assume that the distribution of the concentration is normal. Since P(X≥7666 | μ=7640) = [ the process exceeds the government limit. (Round to four decimal places as needed.) negligible, the observed x evidence that the population mean for is not is

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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Government regulations dictate that for any production process involving a certain toxic chemical, the water in the output of the process must not exceed 7640 parts per million (ppm) of the chemical. For a particular process of concern, the water sample was collected by a manufacturer 25 times randomly and the sample average x was 7666 ppm. It is known from historical data that the standard deviation σ is 130 ppm. Complete parts (a) and (b) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) What is the probability that the sample average in this experiment would exceed the government limit if the population mean is equal to the limit? Use the Central Limit Theorem. The probability is (Round to four decimal places as needed.) (b) Is an observed x = 7666 in this experiment firm evidence that the population mean for the process exceeds the government limit? Answer your question by computing P (X≥ 7666 | μ=7640). Assume that the distribution of the concentration is normal. Since P(X≥ 7666 | μ=7640) = ☐ the process exceeds the government limit. (Round to four decimal places as needed.) negligible, the observed x evidence that the population mean for is not is
Transcribed Image Text:Government regulations dictate that for any production process involving a certain toxic chemical, the water in the output of the process must not exceed 7640 parts per million (ppm) of the chemical. For a particular process of concern, the water sample was collected by a manufacturer 25 times randomly and the sample average x was 7666 ppm. It is known from historical data that the standard deviation σ is 130 ppm. Complete parts (a) and (b) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) What is the probability that the sample average in this experiment would exceed the government limit if the population mean is equal to the limit? Use the Central Limit Theorem. The probability is (Round to four decimal places as needed.) (b) Is an observed x = 7666 in this experiment firm evidence that the population mean for the process exceeds the government limit? Answer your question by computing P (X≥ 7666 | μ=7640). Assume that the distribution of the concentration is normal. Since P(X≥ 7666 | μ=7640) = ☐ the process exceeds the government limit. (Round to four decimal places as needed.) negligible, the observed x evidence that the population mean for is not is
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Transcribed Image Text:الها Areas under the Normal Curve > > 2 .00 Areas under the Normal Curve .01 .02 .03 .04 0.0129 0.4443 .01 .02 .04 z .00 .01 .02 .03 .04 .05 .06 .07 -3.4 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 -3.3 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 -3.2 0.0007 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0010 0.0009 -3.1 0.0009 0.0009 0.0008 0.0008 0.0008 -3.0 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026 -2.7 -2.6 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036 -2.6 -2.5 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 -2.5 -2.4 0.0082 0.0078 0.0075 0.0080 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 -2.4 -2.3 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094 0.0091 0.0089 0.0087 0.0084 -2.3 -2.2 0.0139 0.0136 0.0132 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0.8962 0.8980 0.8997 0.9015 1.2 1.3 0.9032 0.9049 0.9066 0.9082 0.9099 0.9115 0.9131 0.9147 0.9162 0.9177 1.3 1.4 0.9192 0.9207 0.9222 0.9236 0.9251 0.9265 0.9279 0.9292 0.9306 0.9319 1.4 1.5 0.9332 0.9345 0.9357 0.9370 0.9382 0.9394 0.9406 0.9418 0.9429 0.9441 1.5 0.9463 0.9452 0.9474 0.9484 0.9495 0.9505 0.9515 1.6 0.9525 0.9535 0.9545 0.9554 0.9564 0.9573 0.9582 0.9591 0.9599 0.9608 0.9616 0.9625 0.9633 1.7 0.9649 0.9656 0.9641 0.9664 0.9671 0.9693 0.9678 0.9686 0.9706 0.9699 1.8 0.9713 0.9719 0.9726 0.9732 0.9738 0.9744 0.9750 0.9756 0.9761 0.9767 1.9 2.0 0.9772 0.9778 0.9783 0.9788 0.9793 0.9798 0.9803 0.9808 0.9812 0.9817 2.0 0.9821 0.9826 0.9830 0.9834 0.9838 0.9842 0.9846 0.9850 0.9854 0.9857 2.1 2.2 0.9861 0.9864 0.9868 0.9871 0.9875 0.9878 0.9881 0.9884 0.9887 0.9890 2.2 2.3 0.9893 0.9896 0.9898 0.9901 0.9904 0.9906 0.9909 0.9911 0.9913 0.9916 2.3 2.4 0.9918 0.9920 0.9922 0.9925 0.9927 0.9929 0.9931 0.9932 0.9934 0.9936 2.4 2.5 0.9938 0.9940 0.9941 0.9943 0.9945 0.9946 0.9948 0.9949 0.9951 0.9952 2.5 2.6 0.9953 0.9955 0.9956 0.9957 0.9959 0.9960 0.9961 0.9963 0.9964 0.9962 2.6 0.9965 2.7 0.9966 0.9967 0.9968 0.9970 0.9969 0.9971 0.9972 0.9973 0.9974 2.7 回 2.8 0.9974 0.9975 0.9976 0.9977 0.9977 0.9978 0.9979 0.9979 0.9980 0.9981 2.8 0.9982 0.9982 0.9983 0.9984 0.9984 0.9985 0.9987 0.9987 0.9987 0.9988 0.9988 0.9989 0.9989 0.9990 0.9991 .05 .06 .08 .09 0.5359 0.0 0.5753 0.1 0.6141 0.2 0.9985 0.9986 0.9986 2.9 A 3.2 3.3 A 3.4 0.9991 0.9991 0.9992 0.9992 0.9992 0.9993 0.9993 0.9994 0.9994 0.9994 0.9994 0.9994 0.9995 0.9995 0.9995 3.2 0.9989 0.9990 0.9990 3.0 0.9992 0.9993 0.9993 3.1 2 0.9995 0.9995 0.9997 0.9997 .00 .01 0.9995 0.9996 0.9997 0.9997 .02 .03 0.9996 0.9996 0.9997 0.9997 0.9996 0.9997 .04 .05 .06 0.9996 0.9996 0.9997 0.9997 .07 .08 0.9997 0.9998 .09 3.3 3.4 .09 2
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