Given the function y = 8e-2x + 7 sec² 5x - 4 ln x³, find y'. Solution: 4(3)x² 3 12 X ------- 12 1 -32xe +70 sec² 5x tan 5x -2x 1 1 ----... ***** M +8(-4x)e-²x² +7 (2) sec 5x (tan 5x sec 5x)(5) -- +8(-4x)e-2x² +7 (2) sec 5x (sec² 5x) (5) y' y' -------- -32xe -2x² + 140 sec³ 5x

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