Given the function : f(x) = x³ + 39x² – 2462x - 3444; solve using Regula-Falsi Method with initial values of (30.00, 40.00) 1st iteration xn = xp = xnew = 2nd iteration xn= xp = xnew = 3rd iteration xn= xp = xnew = 4th iteration xn= xp = xnew = 5th iteration xn = xp = xnew = f(xn) = f(xp) = f(xnew) = f(xn) = f(xp) = f(xnew) = f(xn) = f(xp) = f(xnew) = f(xn) = f(xp) = f(xnew) = f(xn) = f(xp) = f(xnew) =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 54E
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Given the function : f(x) = x³ + 39x² – 2462x - 3444; solve using Regula-Falsi Method with initial values of (30.00, 40.00)
1st iteration
xn =
xp =
xnew =
2nd iteration
xn=
xp =
xnew =
3rd iteration
xn=
xp =
xnew =
4th iteration
xn=
xp =
xnew =
5th iteration
xn =
xp =
xnew =
f(xn) =
f(xp) =
f(xnew) =
f(xn) =
f(xp) =
f(xnew) =
f(xn) =
f(xp) =
f(xnew) =
f(xn) =
f(xp) =
f(xnew) =
f(xn) =
f(xp) =
f(xnew) =
Transcribed Image Text:Given the function : f(x) = x³ + 39x² – 2462x - 3444; solve using Regula-Falsi Method with initial values of (30.00, 40.00) 1st iteration xn = xp = xnew = 2nd iteration xn= xp = xnew = 3rd iteration xn= xp = xnew = 4th iteration xn= xp = xnew = 5th iteration xn = xp = xnew = f(xn) = f(xp) = f(xnew) = f(xn) = f(xp) = f(xnew) = f(xn) = f(xp) = f(xnew) = f(xn) = f(xp) = f(xnew) = f(xn) = f(xp) = f(xnew) =
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