Given that the switch in Fig. 5-32 was moved to position 2at 1 = 0 (after it had been in position 1 for a long time)and then returned to position 1 at t= 10 s, determine thevoltage response v(1) for 1 ≥ 0 and evaluate it for V₁ = 20 V.R₁ = 80 ks2, R₂ = 20 k2, and C= 0.25 mF.1010 s4

Answered: Image /qna-images/answer/307773ec-ff7d-4948-a128-5faf02cf795a.jpg

Answered: Given that the switch in Fig. 5-32 was…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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en the following circuit below, at t = 0 the switch closes: R₁ m R3 m + Vs Vs = 18V X t=0 m R₂ R₁ = 3kn R4 = 6kN 6ΚΩ C = R₂ 6ΚΩ C = 100µF R3 = vo(t) + M 12ΚΩ RA Use the differential equation method to determine the output voltage
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the questions here are for the follow up answer. the explanation is amazing but i have two questions. when the circuit is open if a capacitor is present can i always consider a voltage source of value 1v and solve accordingly or are there other conditions linked to it? the 2nd one is why is vc(0-)=vc(0+)=vab(0-)-3ix? and the last question is where did u get the relation in t= infinity? the oen for vc(t)=vc(infinity)..... and why is ic(t)=ix(t)=Cdvc/dt? and why is VAB(t0=3IX+vc(t) please answer all my concerns and i will give a thumbs up ofcourse thnk you!
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Given that the switch in Fig. 5-32 was moved to position 2 at 1 = 0 (after it had been in position 1 for a long time) and then returned to position 1 at t= 10 s, determine the voltage response v(1) for 1 ≥ 0 and evaluate it for V₁ = 20 V, R₁ = 80 k2, R₂ = 20 k2, and C = 0.25 mF. 10