Given a square with area of 9 square units, find the area of the regular hexagon of the same perimeter? Solution: S = 1246 = 2 apothem = 2 a = √3 area = 24 tan tan (π (1-2)) (n- (π (6-2)) san 을 + (2) (3) (6) ama = 10.3923 sq. units

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