Give English language translations of the following wffs ifL(x, y): x loves yH(x): x is handsomeM(x): x is a manP(x): x is prettyW(x): x is a womanj: Johnk. KathyL(x. y): x loves yа. Н() Л L(#)b. (Vx)[M(x) → H(x)]c. (Vx)(W(x) → (Vy)[L(x, y) → M(y) ^H(y)])d. (3x)[M(x) ^ H(x) ^ L(x, k)]е. Вx) (W(x) Л Р() Л ()Le, y) — НО) Л М(У))f. (Vx)[W(x) ^ P(x) →L(j, x)]

a. H(j) ∧ L(k,j) John is handsome and Kathy loves John.

Answered: Give English language translations of…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Implement the following two functions that allow breaking a string into non-empty tokens using a given delimiter in c language . For example, ● For a string “abc-EFG-hi”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc-EFG---hi-”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc”, and a delimiter ‘ ’ : the list of tokens is [“abc”] ● For a string “++abc++”, and a delimiter ‘+’ : the list of tokens is [“abc”] That is, we break the string using the given delimiter, and the tokens are only the non-empty substrings. The function count_tokens gets a string str, and a char delim, and returns the number of tokens in the string separated by delim. int count_tokens(const char* str, char delim); For example● count_tokens("abc-EFG--",'-')needstoreturn2. ● count_tokens("++a+b+c",'+')needstoreturn3.● count_tokens("***",'*')needstoreturn0.The function get_tokens gets a string str, and a char delim, and returns the…
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