G1 12 MVA X₁ = 0,12 pu 11.8 KV O 1.2 33 KV- 6,6 KV- 1.28 1.196 1.32 1.3 T₁12 MVA, X Line-1, Z₁ G2 According to the generators base, the magnitude of fault current in per unit is 1.256 12 MVA X₁ = 0.15 pu 0.12 pu (9.45 + 12.6) ohm T₂3 MVA, X120,08 pu = (0.54 +0.40) ohm Line-2

G1 12 MVA X₁ = 0,12 pu 11.8 KV O 1.2 33 KV- 6,6 KV- 1.28 1.196 1.32 1.3 T₁12 MVA, X Line-1, Z₁ G2 According to the generators base, the magnitude of fault current in per unit is 1.256 12 MVA X₁ = 0.15 pu 0.12 pu (9.45 + 12.6) ohm T₂3 MVA, X120,08 pu = (0.54 +0.40) ohm Line-2

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.4MCQ

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Concept explainers

Single Phase Transformer

A single-phase transformer is a type of power transformer. It is an electrical device that accepts converts the single phase alternating power into single phase alternating power. In this power conversion the voltage is stepped up or down. If the voltage is stepped up, the current will be stepped down and if the voltage is stepped down, the current will be stepped up.

Question

12 MVA
X₁ = 0.12 pu
11.8 KV
O 1.2
33 KV-
6,6 KV-
1.28
1.196
1.32
1.3
G2
T₁12 MVA, X 0.12 pu
According to the generators
base, the magnitude of fault
current in per unit is
1.256
12 MVA
X = 0,15 pu
Line-1, Z=(9.45+12.6) ohm
T₂3 MVA, X2 0,08 pu
Z=(0.54+0.40) ohm
Line-2

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