function FUN(n) 2: for i +1 ton do 3: 4: while x > 0 do x + x – i end while 5: 6: 7: end for 8: end function What is the time complexity of the function above? Select one: O n O nlogn O n² log n O n?
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function FUN(n) 2: for i +1 ton do 3: 4: while x > 0 do x + x – i end while 5: 6: 7: end for 8: end function What is the time complexity of the function above? Select one: O n O nlogn O n² log n O n?
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- What does the function return for any positive values of x and n ? The answer should be a general formula in terms of x and n. int what_do_I_do ( int x, int n ) { if ( n = = 1 ) return x; else return x + what_do_I_do ( x, n – 1 ); } C++ be quick pleasePart (a) Write a python function that computes the binomial coefficient ("). The function should return the correct answer for any positive integer n and k where k=m pass Part (c) Suppose that the number of people in the trial is 100. Then: • Plot a curve that shows how the probability of type 1 error changes with the choice of m, for m = 1,...n assuming that the null hypothesis holds (in red), • On the same picture, plot the probability of type 2 error vs the value of m in the case in which the new drug is effective with proability 0.68 (in blue). You can plot the two curves using matplotlib.pyplot. You can select the color by passing color='r' or color='b' to the plt.plot() function. [4]: n - 100 # your code here def plot_curve (): pass [5]: plot_curve() Part (d) Based on the picture above, what value of m do you think would be suitable to keep both type 1 and type 2 error small at the same time? (You may assume that the company claims the new drug has 68% accuracy) [6]: # your…497 Bytes Write a recursive function that returns the sum of the digits of a given integer.Input format :Integer NOutput format :Sum of digits of NConstraints :0 <= N <= 10^9Sample Input 1 :12345Sample Output 1 :15Sample Input 2 :9Sample Output 2 :9 Solution:///////////// public class solution { public static int sumOfDigits(int input){ int sum; if(input<10){ return input; } sum = (input % 10) + sumOfDigits(input / 10); return sum; }}. .
- CodeW X bFor fun X C Solved x b Answer + x https://codeworko... CodeWorkout X265: Recursion Programmlng Exercise: GCD The greatest common divisor (GCD) for a pair of numbers is the largest positive integer that divides both numbers without remainder. For function GCD , write the missing base case condition and action. This function will compute the greatest common divisor of x and y.You can assume that x and y are both positive integers and that x > y. Greatest common divisor is computed as follows: = x and GCD(x, y) = GCD(y, x % y). Examples: GCD (6, 4) -> 2 Your An swer: 1 public int GCD(int x, int y) { if > { 2. > 3. } else { 4. return GCD(y, x % y); 9. { 7. 1:09 AM 50°F Clear 1V 1. 12/4/2021 甲Code in Python Write a function, print_integers_less_than(n), which takes an integer parameter n and prints each integer k which is at least 0 and is less than n, in ascending order. Hint: use a simple for loop. For example: Test Result print_integers_less_than(2) 0 1 print_integers_less_than(5) 0 1 2 3 4 print_integers_less_than(-3)Abraham Series to Compute Write a well-documented Python program, hmwk4Q2.py, that calculates. Construct a function abr_pi.py(N) accepts an integer N and returns an estimate of computing the Abraham Series using N terms. The series is: [2(1) 3ần 2n + 1 12=0 Have the main() call upon your function for various values of N to ensure it is correctly working. π =
- SA=[1; 2; 3] THEN A=A' , THE RESULT * IS COLUMN O NON O ROW O A*A = A*2 TRUE O False O MATLAB IS EASY TO LEARN AND SIMPLE TO USE LOADS OF BUILT IN FUNCTIONS O ALL ANSWERWe define the following recursive Python function: def cool (n): if n==0: return 2 if n==1: return 1 return cool(n-1)+2*cool(n-2) where n is assumed to be a natural number. Change the cool function into a dynamic programming one: def coolDP (n) using memoisation. Note that you can use Python dictionaries for this function.Q 1.Consider the following functions f1 and f2:int f1(int n) { if (n == 0) { return 1; } else { return f2(4, f1(n – 1)); }} int f2(int n1, int n2) { if (n1 == 0) { return 0; }else { return n2 + f2(n1 – 1, n2); }} a. Evaluate the value of f1(7)? b. Analyze the computational complexity of the f1 function expressed in terms of big-O notation?
- 1. Given the following function: int Fn (int N) { } if (N == 0) return 2; else return N + Fn (N/3); a) What type of function is this, Iterative or Recursive? Give justification. b) Given N = 17, what will be the output from this function? Show your work.Write a recursive Python function that matches the following docstring: '''Function -- sum_fivesSums all positive multiples of five between 0 and some integer, n, inclusive.Parameters:n -- an integer.Returns:The sum of all positive multiples of five up to and including n.''' Examples: sum_fives(1) returns 0 sum_fives(5) returns 5 sum_fives(10) returns 15IN SCALA PLEASE COULD YOU COMPLETE THE FUNCTIONS: is_pow_of_two, is_hard, last_odd //(1) Complete the collatz function below. It should // recursively calculate the number of steps needed // until the collatz series reaches the number 1. // If needed, you can use an auxiliary function that // performs the recursion. The function should expect // arguments in the range of 1 to 1 Million. def collatz(n: Long) : Long = { if(n == 1) 0else if(n % 2 == 0) 1 + collatz(n/2) else1 + collatz(n*3 + 1) } //(2) Complete the collatz_max function below. It should // calculate how many steps are needed for each number // from 1 up to a bound and then calculate the maximum number of // steps and the corresponding number that needs that many // steps. Again, you should expect bounds in the range of 1 // up to 1 Million. The first component of the pair is // the maximum number of steps and the second is the // corresponding number. def collatz_max(bnd: Long) : (Long, Long) = { ((1.toLong to…