From the field notes of a closed traverse shown below, adjust the traverse:DISTANCESDue North 400.00 m800.00 m700.00 m600.00 m966.34 mLINES BEARINGАВВСN45°ES60°ECDDES20°WEAS86°59'Wa. Compute the correction of latitude on line CD using transit rule.b. Compute the correction of latitude on line CD using compass rule.c. Compute the linear error of closure.d. Compute the relative error of precision.

The concept used:- Computing Latitudes: Lat. = length x cos α Computing Departures :…

Answered: From the field notes of a closed…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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3. Complete the table and sketch the traverse, assuming no measurements were obtained for line EF. LATITUDE DEPARTURE LINE LENGTH, m BEARING N (+) S() E(+) W(-) АВ N 5°30'8.33" E 490.71 47.27 BC 587.12 608.89 CD 327.41 786.78 DE 1002.76 218.32 EF FA 375.01 544.64 SUM
Direction: Given the following data on the table. Fill up the needed data. Balance the traverse by transit rule. Solve the area by DPD or DMD. Sketch the traverse. All values must be in decimal places. COMPUTED ADJUSTED DEPARTURE LIN ADJUST ADJUST DISTAN СЕ (M) AZIMUT COMPUTED ADJUSTED LATITUDE ADJUST ED AZIMUT BEARIN DPD DOUBLE E G LATITUDE DEPARTURE ED DISTAN СЕ ED AREA (from S) BEARIN H (nearest (nearest minute) minute) +NL -SL +ED -WD +NL -SL +ED -WD АВ E S 70-29 N 10-00 650.00 ВС 895.00 CD S 26-28 315.00 DE S 65-33 W EA 875.00 410.00 N 45-31 W ТОTAL LEC : RP (nearest hundred) AREA ..
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the area of the traverse using DPD Method. Line Length Bearing AB 413.600 m N 09°30’ W BC 304.380 m N 55°06’ W CD 407.210 m S 57°35’ W DE Unknown S 04°05’ E EA 649.630 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the Area of the Traverse. Line Length Bearing AB 589.060 m N 87°30’ E BC 391.730 m N 07°02’ E CD 291.860 m N 30°30’ E DE 656.980 m S 42°45’ E EF 654.060 m Unknown FA 686.660 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
Direction: Given the following data on the table. Fill up the needed data. Balance the traverse by transit rule. Solve the area by DPD or DMD. Sketch the traverse. All values must be in decimal places. LIN BEARIN E DISTAN AZIMUT COMPUTED COMPUTED ADJUSTED LATITUDE ADJUSTED DEPARTURE ADJUST ADJUST ED DOUBLE ADJUST ED DPD G СЕ H LATITUDE DEPARTURE ED AREA (M) (from DISTAN BEARIN AZIMUT S) СЕ H (nearest (nearest minute) minute) +NL -SL +ED -WD +NL -SL +ED -WD АВ N 10-00 650.00 BC S 70-29 895.00 1/2 CD S 26-28 315.00 E DE S 65-33 875.00 EA N 45-31 410.00 ТОTAL LEC : RP (nearest hundred) AREA ...
Q3): The following data were collected while running a closed traverse ABCDA. Calculate: 1- Coordinates of B (Easting and Northing). N Line AB BC CD DA 4- 5- Distance BC and CD. 6- Coordinates of C (Easting and Northing). Interior angles A and B Length(m) 330 827 Sum= 2435.15 Azimuth 181°25' 89°50' 355°00' 264°18'20" Point A B C D A (calculated) = Easting 500 B 1323.167 Northing 500 582.059 A= B= Angles
From the following traverse notes, compute the corrected distance of line CD using Transit Rule. LINE BEARING DISTANCE LATITUDE DEPARTURE А-В N 15 30' E 60.00 m + 57.81 16.03 В-С S 82 23' E 72.69 9.63 72.04 S 17° 20' E - 42.79 C-D 44.83 13.36 D-E S 70 36' W 56.45 18.75 53.25 E-A N 74 20' W 50.00 + 13.50 48.14
Q3): The following data were collected while running a closed traverse ABCDA. Calculate: 1- Coordinates of B (Easting and Northing). N Line AB BC CD DA 4- Interior angles A and B 5- Distance BC and CD. Length (m) 330 827 Sum= 2435.15 Azimuth 181°25' 89°50' 355°00' 264°18'20" Point A B C D A (calculated) = Easting 500 B 1323.167 Northing 500 582.059 A= B= Angles
2. AREA BY DMD. For the given sets of adjusted latitudes and adjusted departures shown in the accompanying tabulations, determine the area of each traverse (in sq.m. and ha.) using the double meridian distance method. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE -w AB 7i5.20 1200.53 BC 414.29 401.78 CD 419.88 1606.43 1735.58 DE 200.70 EF 617.59 456.66 FG 849.91 202.83 GA 233.53 677.83 Sums +2383.40 -2383.40 +2482.97 -2482.97 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE -S 1-2 281.28 281.06 2-3 168.75 449.32 3-4 337.56 281.22 4-5 112,50 450.66 450.03 225.08 5-6 6-1 450.06 335.86 Sums +900.09m-900.09 m+10I1.60MFIOT1.60m
AREA BY DMD. For the given sets of adjusted latitudes and adjusted departures shown in the accompanying tabulations, determine the area of each traverse (in sq.m. and ha.) using the double meridian distance method. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S AB 7i5.20 1200.53 вс CD DE 401.78 414.29 1735.58 419.88 1606.43 456.66 200.70 EF 617.59 FG 849.91 202.83 GA 233.53 677.83 Sums +2383.40 -2383.40 +2482.97 -2482.97 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N -S +E - w 281.06 1-2 2-3 281.28 168.75 449.32 337.56 281.22 T12,50 450.66 450.03 225.08 450.06 335.86 Sums +900.09 m 900.09 m+1011.60mHio11.6Om N3456- -2345
Given the tabulated measurement of the closed traverse as shown. Determine the area of the traverse using DPD Method. Line Length Bearing AB 413.600 m N 09°30’ W BC 304.380 m N 55°06’ W CD 407.210 m S 57°35’ W DE Unknown S 04°05’ E EA 649.630 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.

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