From the Boolean expression shown, construct the equivalent logic diagram and show the truth table. F = [(AOB) + AC ]O BC
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![From the Boolean expression shown, construct the equivalent logic
diagram and show the truth table.
F = [(AOB) +ĀC]O BC
OUTPUTS
INPUTS
G1
G2
G3
G4
G5
G6
G7
A
в
1
1
1
1
1
1
1
1
1,
1,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F77d74bdf-7175-428d-9d9a-4b4102826651%2Fde7bb7fb-70cd-482b-b930-891067c6d67f%2Fkmmdn86_processed.png&w=3840&q=75)
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- Create a logic diagram out of this boolean expression. B'D+C'D+AB'+BCD' Note: All inputs A B C and D must be together.Using Boolean theorems, simplify the output expression for the circuit in the figure. Show all the steps used to simplify the expression.(m. Simplify the given expression using Boolean algebra and implement the simphifie expression using basic logic gates. Y = A.B.C+ A.B.C + A.B.C + A.B.C
- Draw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = FRequired: 0. Write Boolean expression For each Row in Table.1. Draw a k-map table based on the logic/truth table above. explain how you make k-map.2. Group the implicants (those 1s inside the k-map table) accordingly. Allowed groupings are 1, 2, 4, 8, 16, …, n.3. Write the Boolean expression based on the k-map table.4. Draw the logic gates diagram of the Boolean expression. Note:- please Solve with complete explanation.I Need step by step with explanation as I*m beginner in K-Map. will Surely Upvote. Will appreciate if Handwritten Solution.Simplify the following Boolean expressions using Karnaugh Map and draw the logic circuits. f = wxyz + wxyz + wxyż + wxỹz + wxyz + wxyz + wxỹz + wãyz
- Problem: Derive the logic expressions for a circuit that compares two unsigned numbers: X = x2x1xo and Y = = y2y1yo and generates three outputs: XGY, XEY, and XLY. One of these outputs is set to 1 to indicate that X is greater than, equal to, or less than Y, respectively.Q2 Determine the Boolean expression for the logic circuit shown in Figure below. Simplify the Boolean expression using Boolean Laws and De Morgan's theorem. Redraw the logic circuit using the simplified Boolean expression and develop its truth table. В Co- Do FSimplify the following Boolean expression to a minimum number of literals and draw the logic diagrams of the circuits that implement the original and the simplified expressions: ( xyz + bx’ + xyz’ ) ( xd + x’d )
- Draw the logic circuits for the following Boolean expressions and simplify the logic expressions using theorems of Boolean algebra. (Ā+B)(A+ Ē + D)DIn boolean algebra, the bar sign (-) indicates O a. NOT operation O b. OR operation O c. None of the options given O d. AND operationShow the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A.B+C+(C+B). D 2) Y= A.B.C+B.D. (AOP)+C 3) Y= A.B (C + D) + D+ A B