Analog electronics For the network of Fig. 8.39, determine:OZ₁JF330 ΚΩ-08 V102.7 kQ2HEhfe = 120hie = 1.175 khoe = 20 μA/VZo(a) Z₁.(b) Zo.(c) Av.(d) A₁.Figure 8.39

Answered: For the network of Fig. 8.39,…

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Electrical Engineering

For the network of Fig. 8.39, determine: w 330 ΚΩ -08 V 2.7 ΚΩ (a) Z₁. (b) Zo. (c) Av. (d) A₁.

Introductory Circuit Analysis (13th Edition)

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Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

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Current Division Method

The generalized current divider formula is given by the following relation below,

Question

Analog electronics

For the network of Fig. 8.39, determine:
O
Z₁
JF
330 ΚΩ
-08 V
10
2.7 kQ2
HE
hfe = 120
hie = 1.175 k
hoe = 20 μA/V
Zo
(a) Z₁.
(b) Zo.
(c) Av.
(d) A₁.
Figure 8.39

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