For the logic circuit shown * below, the output (F) is 2 A B F 10 11 12 13 14 15 F=B'D'+BD F=AB+A'D' (F) is non of these functions F=A'D+B'D F=AC+B'D' 4-to-16 Decoder 3. 2. 1.
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- USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…Write a VHDL program to implement the combinational logic circuit in the following figure. HA A>B A>E B The circuit contains three input signals r, q and s, and one output sigal z. All signals are 1 bit only. In the circuit, there are two 2-to-1 multiplexers and two 2-input comparators. The two comparators should be implemented using component.answere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.
- H.W :- 1) A four logic-signal A,B,C,D are being used to represent a 4-bit binary number with A as the LSB and D as the MSB. The binary inputs are fed to a logic circuit that produces a logic 1 (HIGH) output only when the binary number is greater than 01102-610. Design this circuit. 2) repeat problem 1 for the output will be 0 (LOW) when the binary input is less than 01112-710- Saleem LateefFrom the BCD code whose block diagram is given in the figure below, you can find the 7-segment LED display (with common anode) code. Solving combinational logic circuit will be designed. This type of commercially produced decoder is integrated State the features you consider important by researching the circuits. BCD input at the output of the decoder For the 0-9 values of the information information, the following indicator figures will be seen and the values other than these it will be considered arbitrary. Since the 7-segment LED display has a common anode, The logic "0" will be applied to the burned parts. Draw this circuit.From the BCD code whose block diagram is given in the figure below, you can find the 7-segment LED display (with common anode) code. Solving combinational logic circuit will be designed. This type of commercially produced decoder is integrated State the features you consider important by researching the circuits. BCD input at the output of the decoder For the 0-9 values of the information information, the following indicator figures will be seen and the values other than these it will be considered arbitrary. Since the 7-segment LED display has a common anode, Logic "0" will be applied to the burned parts. The accuracy of the logic circuit you will design Create the table and find the output expressions by shrinking the table with the Karnaugh diagram method.
- Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).Write a VHDL code for the following simple logic circuit. D- X1 X2 f X3From the BCD code whose block diagram is given in the figure below, you can find the 7-segment LED display (with common anode) code. Solving combinational logic circuit will be designed. This type of commercially produced decoder is integrated State the features you consider important by researching the circuits. BCD input at the output of the decoder For the 0-9 values of the information information, the following display figures will be seen and the values other than these it will be considered arbitrary. Since the 7-segment LED display has a common anode, Logic "0" will be applied in response to the burned parts. The accuracy of the logic circuit you will design Create the table and find the output expressions by shrinking the table with the Karnaugh diagram method.
- (c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).Consider the circuit below. The switches are controlled by logic variables such that, if A is high, switch A is closed, and if A is low, switch A is open. Conversely, if B is high, the switch labeled is open, and if B is low, the switch labeled is closed. The output variable is high if the output voltage is 5V, and the output variable is low if the output voltage is zero. a. Write a logic expression for the output variable. b. Construct the truth table for the circuit. A Logic 1 5V(+ B C Logic 0 RA three input logic functipn will provide a logic high output only when twp (and two only) of the inputs are logic highs. For all other input possibilities, a logic zero is provided on the output. What is the logic expression? A. Y=A'B'C+A'BC'+AB'C' B. Y=AB'C+A'BC+ABC' C. Y=AB'C+ABC+A'B'C' D. Y=ABC'+AB'C+A'B'C'