For the given circuit, assuming an ideal diode, the value of current I will be: }25 kn 2.5 O a. 5 mA O b. 1 mA O c. 2 mA O d. 0 mA
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- How is a solid-state diode tested? Explain.Given the following circuit with VDD = 9.5 V, R = 3.2 kn, then the current Iis: Use the CVD model for the diode, with Vp= 0.65 V. VDR I a. 2.968750 A b. 0 A c. 0.002766 A d. 0.002969 A e. 2.765625 A R ww + VouO 9:.0 A docs.google.com * ZAIN IQ l. Q3/B: Assume an ideal diode model for all the diodes in the circuit below. calculate voltages and currents through D1 and D2 9kQ 1N1199C R2 D1 18KQ 1N1199C D3 1N1199C V2 =12 V R3 1kQ R4 5kQ 1.22 V 11 mA 0.5 A O VD1 ID1 VD2 ID2 صفحة 4 من 6
- For a certain 12 V zener diode, a 10 mA change in zener current produces a 0.05 V change in zener voltage. The zener impedance for this current range is Ca. 50 O b. 10 c.0.10 d. 100For a certain 12 V zener diode, a 10 mA change in zener current produces a 0.05 V change in zener voltage. The zener impedance for this current range is O a. 50 b. 10 c.0.10 Od. 100The impedance of Zener diode in the Circuit when the reverse current in the diode increases from 20 mA to 30 mA as the zener voltage changes from 4.6 V to 4.71 V is O a. 90 ohms O b. 11 ohms O c. 35 ohms O d. None of the Above
- Given the following circuit with VDD= 9.2 V, R=2.3 k2, then the current Iis: Use the CVD model for the diode, with VD = 0.65 V. I VDD a. 0.004000 A O b. 3.717391 A OC. 0 A d. 4.000000 A e. 0.003717 A R + VD -For the circuit below, assume the diodes operate with a constant voltage drop of .7V, find Vx, Vy, VD4 and ID2. 15V 15V Allt V1 V2 R1 1k IDC 1mA Vx R2 2k ww D1N4002 Vy D1N4002 7D1 D1N4002 D2 D3 R3 1k D4 D1N4002Using the ideal diode model, find the output voltage for the input voltage of the following circuit and graph it in detail. (a) (b) R₁ D₁ www ww R3 D2 (a) R₁ D₁ www + + D2 R2 vo Vo R₂ (b)
- Determine the current V, of the figure below using the approximate equivalent model for the diode. 10 mA 2.2 k2 22 kAssuming ideal diode the voltage across the resistor R2 in the circuit shown in the Figure is: R1 E = +12V0- 2.2k2 RE1.8kN E, = +4V A 4.0 V 7.6 V 3.6 V D 4.4 VGiven the following circuit with VDD = 9.5 V, R = 3.2 k2, then the current Iis: Use the CVD model for the diode, with VD = 0.65 V. VDD I a. 0 A O b. 0.002766 A c. 0.002969 A d. 2.968750 A e. 2.765625 A R N V₂