For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and finc the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The scores of three students in a study group on a test are 94, 92, 96. Use a sample size of 3. J. 92,96,94 x=94 M. 94,94,96 x=94.67 P. 96,92,96 x=94.67 S. 92,92,96 x=93.33 V. 96,92,92 x = 93.33 Y. 96,94,92 x=94 The mean of the sampling distribution is 94.00 (Round to two decimal places as needed.) The standard deviation of the sampling distribution is. (Round to two decimal places as needed.) K. 92,94,92 x=92.67 N. 94,96,96 x=95.33 Q. 96,94,96 x=95.33 T. 92,96,96 x=94.67 W. 94,92,96 x=94 Z. 96,96,94 x = 95.33 M 94,96,92 x=94 o. 92,96,92 x=93.33 R. 92,94,94 x = 93.33 U. 92,92,92 x=92 x. 96,94,94 x=94.67 96,96,96 x=96

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter10: Statistics
Section10.4: Distributions Of Data
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I need help with the standard deviations of the sampling distribution
For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find
the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population.
The scores of three students in a study group on a test are 94, 92, 96. Use a sample size of 3.
EV
J. 92,96,94 x = 94
M. 94,94,96 x=94.67
96,92,96 x=94.67
92,92,96 x = 93.33
96,92,92 x = 93.33
96,94,92 x=94
LVP.
S
V.
Y.
The mean of the sampling distribution is 94.00
(Round to two decimal places as needed.)
K.
92,94,92 x=92.67
N.
94,96,96 x=95.33
Q. 96,94,96 x = 95.33
MT. 92,96,96 x 94.67
W. 94,92,96 x=94
The standard deviation of the sampling distribution is.
(Round to two decimal places as needed.)
96,96,94 x = 95.33
94,96,92 x=94
O. 92,96,92 x=93.33
R. 92,94,94 x = 93.33
U. 92,92,92 x=92
X. 96,94,94 x = 94.67
96,96,96 x=96
4
Transcribed Image Text:For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The scores of three students in a study group on a test are 94, 92, 96. Use a sample size of 3. EV J. 92,96,94 x = 94 M. 94,94,96 x=94.67 96,92,96 x=94.67 92,92,96 x = 93.33 96,92,92 x = 93.33 96,94,92 x=94 LVP. S V. Y. The mean of the sampling distribution is 94.00 (Round to two decimal places as needed.) K. 92,94,92 x=92.67 N. 94,96,96 x=95.33 Q. 96,94,96 x = 95.33 MT. 92,96,96 x 94.67 W. 94,92,96 x=94 The standard deviation of the sampling distribution is. (Round to two decimal places as needed.) 96,96,94 x = 95.33 94,96,92 x=94 O. 92,96,92 x=93.33 R. 92,94,94 x = 93.33 U. 92,92,92 x=92 X. 96,94,94 x = 94.67 96,96,96 x=96 4
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