For the following reaction, 6.91 grams of methane (CH4) are allowed to react with 27.9 grams of carbon tetrachloride. methane (CH₂) (g) + carbon tetrachloride(g) → dichloromethane (CH₂Cl₂) (9) What is the maximum mass of dichloromethane (CH₂Cl₂) that can be formed? Mass = 9 What is the FORMULA for the limiting reactant?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
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For the following reaction, 6.91 grams of methane (CH4) are allowed to react with 27.9
grams of carbon tetrachloride.
methane (CH₂) (g) + carbon tetrachloride (g) → dichloromethane (CH₂Cl₂) (9)
What is the maximum mass of dichloromethane (CH₂Cl₂) that can be formed?
Mass=
9
What is the FORMULA for the limiting reactant?
What mass of the excess reagent remains after the reaction is complete?
Mass=
9
Transcribed Image Text:For the following reaction, 6.91 grams of methane (CH4) are allowed to react with 27.9 grams of carbon tetrachloride. methane (CH₂) (g) + carbon tetrachloride (g) → dichloromethane (CH₂Cl₂) (9) What is the maximum mass of dichloromethane (CH₂Cl₂) that can be formed? Mass= 9 What is the FORMULA for the limiting reactant? What mass of the excess reagent remains after the reaction is complete? Mass= 9
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