For instruction: j Label The instruction is at address 01000000 00000000 00000000 001110. Given an 26-bit immediate field: 00000000 00000000 00000010 00. Enter the first and last 6 bits of the 32-bit address the CPU will construct. Ex: 000101 00 00000000 00000000 00 Ex: 000110
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- A(n) __________ is a storage location implemented in the CPU.if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical address is O 6243H O 4234H O 6234H O 6324H O 4244H0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h. Add the contents of memory location 451h to AC. Store AC to memory location 8h. Store AC to I/O device number 8h.
- Memory 12200 12201 12202 12203 12204 Content %D AA EE FF 22 What result is produced in the destination operand by execution the following instruction? a- LEA SI[DI+Bx+5] b- LDS SI.[200]What is the effective address that is targeted by the store instruction whose code word in binary is:101011 01000 10001 1111 1111 1111 1100Assume [$t0]=0x400CConsider the following instruction format and the list of opcodes 0101 *Note that all memory contents and addresses are hexadecimal. 0110 0001 0010 0011 Opcode (15.12) 0100 Instruction format Opcode Address(11..0) A portion of the instruction set Load AC from memory Store AC to memory Instruction Add AC from memory - AC + memory Subtract memory from AC - AC - memory Multiply AC by memory - AC*memory Divide AC by memory- AC/memory
- Given following code: 00 9000 01 1150 02 1251 03 5300 04 6420 05 7541 06 8414 07 D20A 08 2523 09 0000 0A 3331 0B B200 0C D20A 0D 2523 0E 0000 50 000A 51 0005 52 0000 Explain what each instruction does in the program, stored in the memory locatons 00 through 0E. When the program stops, what are values in registers R0, R1, R2, R3, R4, R5, and in memory location 52? What does the program do?A digital computer has a memory unit with 24 bits per word. The instruction set consists of 150 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory.Q.) What is the largest unsigned binary number that can be accommodated in one word of memory?Convert the given hex value to its R-format MIPS instruction by completing the following table. The instruction and letters for registers must be in lower case. DO NOT TYPE DOLLAR SIGNS WITH REGISTERS. Hex Opcode (decimal) rs (decimal) rt (decimal) rd (decimal) funct (decimal) Instruction 02488822 O 18 16 17 34 sub s4 $$1 " $ to " LA
- Bus d'adresse Ox0 A7 0 A6 0 AS Oxo 0 A4 0 A3 0 A2 0 A1 Lecture Bus de contrôle Écriture AO Bus de données Mémoire d'Instructions Adr Adr Ctr Ctr Ctr Ox Mémoire de données Clavier Écran CD 0 EN Data Data EN Data EN Data EN Write the instruction STR R2, [R3] in hexadecimal (using 2 bytes). АО A1 DO D1 D d u r D3 D2 09The equivalent GPR-type machine code of the statement: D = ((A/B) + ((B+A) * C))/A can be written in at least how many lines/instructions. 8 9 10 11 Can the following instruction set fit into a 16-bit CPU if each operand uses 4 bits? 12 3-address instructions 62 2-address instructions 31 1-address instructions 14 0-address instructions Yes NoWhat is the hexadecimal address of x5 for each of the following instructions.