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- Check Your Understanding Find the angle between forces F1and F3in Example 2.16.A 500 N, is placed against ladder 15.0 m. long, weight a frietion less wall If the edge of the ladder is at 6o degree angle to the a horizon tal A) Find the horizontal and vertical for ces of the acting the step avea on when a fire fighter weighing s00 N is stand ing a ladder on 4.0 m. a bove the floor. Answer [268 N in direction t x , 1,300 N in direction o y] B) when fire fighter is q.0m above the floor, the ladder slips, a find the coef ficient of static friction between the ladder and the floor A uswer [ o.324]Two forces are applied to the construction bracket as shown. Determine the angle which makes the resultant of the two forces vertical. Determine the magnitude R of the resultant. Assume F₁ = 725 lb, F₂ = 390 lb, a = 69°. F₁ y T F2 O H Answers: e= i R = i lb
- Replace the two forces and one couple acting on the rigid pipe frame by their equivalent resultant force R acting at point O and a couple MO. MC = 30 lb-ft, F = 30 lb, and P = 90 lb. Find only the magnitude of MO in lb.in.Since it is knowwnas a = 30 andt= 10cm, reduce the system of forces in the figure to a single force ww and find the coordinates of the points where the line of action of the resultant force intersects theX and Y axes with its center at point O. wwww 30G C 160AG a) x = 9,6 cm, y= - 4,95 cm b) x=6,7 cm, y=-4,07 cm C)O x=4,62 cm, y= -6,25 cm D. d) O x 7,5 cm, y=-4,33 cmyou loosened a nut W/ wrench lenghh 27 cm. The Mmimina Horce needed to apply to the wrench was 43 N. what was 1orQue created buy force?
- Find the resultant of force Y 390 Ib MATHalino.com 12 30 1 1 300 lb 722 Ib Figure P-265A 10kg block resting on a flat frictionless plane is pushed by a force directed force of 20N 60 deg S to E. What is the mahnitude of net force acting on the block?The leg and cast in the figure weigh 220N (w,). Determine the weight w, and the angle alpha needed so that no force is exerted on the hip joint by the leg plus the cast. 110 N
- SAQ 1 1.2 m D C An 80-kn'm couple shown in the plate is caused by a pair of parallel forces of magnitude F (not shown). Determine: 80 kN m a) the smallest possible value of F, and 1.6 m b) the value of F if the forces act at points A and C and are parallel to the dashed line shown at A. A В 60°The mass of the block = 172 kg First Force applied, Fapp 1 = 225.1 N Second Force applied, Fapp 2 = 330.2 N Find the Normal Force, FnA spring balance indicates a mass of 10.0 g on zero load and 60.3 g with a true load of 50.0 g. Calculate the true load and load force when the indication is 100.0 g. Assume g — 9.81 m/s2.