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- S00 Ib In the fig. shown, compute the ff: (16-18) the resultant using cosine law (force polygon) 60 R = 35 (19-20) the angle of the R measured 500 lb cW from the x- axis.Find the angle between the two given vectors. u = (1, -4, 1), v = (0, 2, –2) %3D Write your answer in degree measure (no need to use the degree symbol), e.g. 45Find the desired ones by randomly typing two A and B vectors in the form below. A = (5) i + (7) j + (10) k B = (2) i + (3) j + (5) k The cross product A x B =? Scalar product A x B =? Intensity A x B =?
- PLEASE HELP ME ASAP :( The structure is supported with cables as shown in Figure 3. All dimensions are in meters. a) If T2= 619 N, solve for F and the remaining cables that can hold the allowable force F acting upward at point A to maintain its equilibrium. b) Solve for the magnitude and direction angles of the resultant force for the three cables if T1= 889 N, T2= 1417 N, T3= 1500 N c) Determine the moment of the resultant force about the axis BC.The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point PFind the following for the vectors v = 10i+11j-2k and u=8i + 15j. a. v. u, |v|, |u| b. the cosine of the angle between v and u c. the scalar component of u in the direction of v d. the vector proj, u a. v. u= (Type an exact answer, using radicals as needed.) |v|= (Type an exact answer, using radicals as needed.) |u| = [ (Type an exact answer, using radicals as needed.) b. The cosine of the angle between v and u is (Type an exact answer, using radicals as needed.) c. The scalar component of u in the direction of v is (Type an exact answer, using radicals as needed.) d. proj, u = (Type your answer in terms of i, j, and k. Type an exact answer, using radicals as needed.)
- A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: Fparallel + Fperpendicular = Ftotal 2013 Michael Swanbom BY NC SA d A FK values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. d 78 in h 57 in g 60 in Variable value 13 in 36 in 45 in F|DA = i. k) lb and b. FL DA =Given the following vectors: S= 3i-j+ 5k P = 2i + 4j - 6k Q = -7i + 2j + 9k Obtain the following operations: 1. Q x P 4. S.P 7. S. (P x Q) 10. Sx S 2. Sx Q 5. Q. P 8. Q. (Sx P) 11. P.P 3. Px S 6. Q. S 9. P. (Qx S) 12. Q. (Q x Q)Graphical Method : Polygon Method F1 - 150N, 30° N of E F2 - 100N, 60° E of S 1) Find the Length and Angle 2) Find Resultant Force Vector Magnitude and %Error 3) Find Resultant Force Vector Direction and %Error
- You are required to calculate the second moment of area about the x-axis for the figure below. a mm b mm a mm a mm One method for calculating the second moment of area is to break up the shape into three parts as shown below. Calculate the second moment of area of segment 2 if: a = 30.67 mm b = 21.14 mm |_x = mm^4 a mm ww eThree forces intersect at point (1, 1, 1). Their magnitude and respective second point of incidence are as follows: 450 lbs (4, -3, 7), 600lbs (-1, 5, -4), 300lbs (-3, 6, -2) 1. Compute the direction cosine on the x-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513 2. Compute the direction cosine on the y-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513 3. Compute the direction cosine on the x-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513Problem 2 Consider the two positions provided in the figure. (a) Using the graphical method to determine the pivot that makes the link AB move from A1B₁ to A₂B2. (b) Analytically find the pivot that makes the link AB move from A₁B₁ to A₂B₂ 1.750 2.656 1.721 0.751 B 2.409 B₂ 0.470