Find the Taylor series for f(x) = e²x at x = 1 and its interval of convergence. Select the correct answer below: n=0 1 e²n 2¹ (x − 1)¹, (-∞, ∞) n! 1e²nqn (x − 1)", (-∞, ∞) n 1 -e²2¹ (x − 1)", (-∞, ∞) n! n=0 ∞ Ο Σe2n (x − 1)",(–00,00) - – n=0

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