Find the Taylor series, centered at c = 3, for the function 1 1 - x² f(x) = (-1)^(4n-3) 8hn! The interval of convergence is: = f(x): Σ n=0 = (x − 3)"
Find the Taylor series, centered at c = 3, for the function 1 1 - x² f(x) = (-1)^(4n-3) 8hn! The interval of convergence is: = f(x): Σ n=0 = (x − 3)"
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 22RE
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