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- I can't find the tangential component of the accelerationFind the tangential and normal components of the acceleration R(t) = (2sint, t, 2cost)If r(t) = cos(lt)i + sin(lt)j - 4tk, compute the tangential and normal components of the acceleration vector. Tangential component aÃ(t) = ¯ Normal component an(t) =
- If r(t) = cos(7t)i + sin(7t)j – 3tk, compute the tangential and normal components of the acceleration vector. COS Tangential component ar(t) Normal component an(t) =find the directional derivative of the function in the direction of the vector u = cos i + sin jFind the rate of change of F at P in the direction of the vector ⟨2,-3,6⟩ and the minimum rate of change of F at P.
- If r(t) = cos(2t)i + sin(2t)j – 4tk, compute the tangential and normal components of the acceleration vector. Tangential component ar(t) = Normal component a(t) =Find the directional derivative of g(a, b) = cos(3a + 4b) at the π point ( along the direction of the vector (-4,-3)Find Components of the Acceleration For the curve defined by 7(t) = (e-t cos(t), eʻ sin(t)) find the unit tangent vector, unit normal vector, normal acceleration, and tangential acceleration at t = 3 T(플) - N(플) - 3 3 AN =
- Find the directional derivative of the given function at the given point in the direction of the given vector vFind the maximum rate of change of f at the given point and the direction in which it occurs. f(p, q, r) = arctan (pqr), (1, 3, 1) maximum rate of change direction vectorFind the tangential and normal components of acceleration for the position vector denoted by i = (cos 2t,-4 sin t, 4t +29)