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Find the slope of the tangent line to the graph of the function at the given point. g(x) = 14 – x; (2, 10) Step 1 Apply the Definition of Tangent Line with slope m, fc + Ax)- (c) m%3D lim Ax Ax - 0 to the given function f(x) = g(x) = 14 x and c 2. %3D At x = 2, g(2) = 10 10 the coordinates of (x, g(x)) are (2, 10 10 ). Step 2 Substitute c = 2 in the formula for slope as follows. + Ax) - g ( 2) m = lim Ax-0 Ax Step 3 At x 2 + Ax, the value of the function is g(2 + Ax) 14 - ( + Ax) Hence, (14 - (2+ Ax))-C m = lim Ax-0 Ax

Find the slope of the tangent line to the graph of the function at the given point. g(x) = 14 – x; (2, 10) Step 1 Apply the Definition of Tangent Line with slope m, fc + Ax)- (c) m%3D lim Ax Ax - 0 to the given function f(x) = g(x) = 14 x and c 2. %3D At x = 2, g(2) = 10 10 the coordinates of (x, g(x)) are (2, 10 10 ). Step 2 Substitute c = 2 in the formula for slope as follows. + Ax) - g ( 2) m = lim Ax-0 Ax Step 3 At x 2 + Ax, the value of the function is g(2 + Ax) 14 - ( + Ax) Hence, (14 - (2+ Ax))-C m = lim Ax-0 Ax

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 36E
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Please solve, make sure to get step 3, thanks so much!
Find the slope of the tangent line to the graph of the function at the given point. g(x) = 14 - x; (2, 10) Step 1 Apply the Definition of Tangent Line with slope m, (c + Ax) – f(c) m%3D lim Ax Ax-0 to the given function f(x) = g(x) = 14 x and c 2. %3D At x = 2, g(2) = 10 10 the coordinates of (x, g(x)) are (2, 10 10 ). Step 2 Substitute c = 2 in the formula for slope as follows. 2 + Ax) -g 2) m = lim Ax-0 Ax Step 3 At x = 2 + Ax, the value of the function is g(2 + Ax)= 14 - ( + Ax) Hence, (14-(2+ Ax))-1 m = lim Ax-0 Ar
Transcribed Image Text:Find the slope of the tangent line to the graph of the function at the given point. g(x) = 14 - x; (2, 10) Step 1 Apply the Definition of Tangent Line with slope m, (c + Ax) – f(c) m%3D lim Ax Ax-0 to the given function f(x) = g(x) = 14 x and c 2. %3D At x = 2, g(2) = 10 10 the coordinates of (x, g(x)) are (2, 10 10 ). Step 2 Substitute c = 2 in the formula for slope as follows. 2 + Ax) -g 2) m = lim Ax-0 Ax Step 3 At x = 2 + Ax, the value of the function is g(2 + Ax)= 14 - ( + Ax) Hence, (14-(2+ Ax))-1 m = lim Ax-0 Ar
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