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Find the IHD and fragment/cleavage
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- CgH,NO2 IR |1* Spectrum IR = NMR Spectrum- 3 THS13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) C₂H₂ NO ₂ expansion 3.0 160 2.0 120 1.0 ppm 10 9 8 7 6 Determine the structure of the compound 5 solvent 80 4 40 3 2 08 (ppm) 1 TMS 0 8 (ppm)13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT C3H,NO2 solvent proton decoupled 200 160 120 80 40 8 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) expansion 4.0 3.0 2.0 1.0 ppm TMS 10 7 6. 4 3 2 1 8 (ppm) Determine the structure of the compound
- 13C NMR Spectrum (100.0 MHz, D20 solution) CgHgNO3 DEPT proton decoupled 200 160 120 80 40 O 8 (ppm) 'H NMR Spectrum (400 MHz, D20 solution) expansions Note: there are 4 protons which exchange with the D20 solvent 4.3 4.1 ppm 3.6 3.4 ppm 1.3 1.1 ppm HаО and HOD in solvent 8 7 6 4 3 2 1 8 (ppm) 10 9 Determine the structure of the compound.Choose the data that best matches this partial structure; the hydrogens represented by the data are in bold: H H H Od, 2H, 4.0 ppm Os, 2H, 7.1 ppm Od, 2H, 6.8 ppm Ot, 2H, 6.9 ppm HFollowing is a 1H-NMR spectrum of 2-butanol. Explain why the CH2 protons appear as a complex multiplet rather than as a simple quintet.
- Draw the structure of the compound identified by the simulated 'H NMR and C NMR spectra. The molecular formula of the compound is C,0H,O. 12 (Blue numbers next to the lines in the 'H NMR spectra indicate the integration values.) H NMR 1H 2H 2H 2H 2H|| 3H 10 8. 4 (dd) g 13C NMR 220 200 180 160 140 120 100 80 60 40 20 8 (ppm) Deduce the structure from the spectra. Select Draw Rings More EraseDraw the structure of the compound identified by the simulated 'H NMR and 13C NMR spectra. The molecular formula of the compound is C1,H120. (Blue numbers next to the lines in the 'H NMR spectra indicate the integration values.) Η NMR 1H 2H 2H 2H 2H 3H| 10 8 4 2 8 (ppm) 13C NMR 220 200 180 160 140 120 100 80 60 40 20 d (ppm)H NMR (300 mMHz, CDC13, 21C) 0.92 ppm (t, 3H, J = 7Hz), 1.20 (s, 6H), 1.50 (q, 2H, J = 7 Hz), 1.64 (broad singlet, 1H). Select the correct structure for this molecule. A B OH OH O to o HO E
- 9 ¹H-NMR Spectra 2 M.F. = C₁₁H₁2O 15 15 -00 8 15 15 7 1 S 6 O) 15 15 5 PPM 4 21 -♡ 3 2 3) 0¹H-NMR Spectra 3 M.F. = C₂H₁3NO 1 S 10 -00 8 6 PPM 4 N 21 3 ſ 2[2] -~ 2 3 jA compound has the molecular formula: C4H8O2 and gives the following C-13 NMR spectrum. Provide the most likely functional groups for each signal. nmrsim presentation 1 1 C:Bruken Topspin3.5pl7 examdata -170.7658 150 100 d 170.8 (O CH3) ; 60.4 (OCH2); 20.8, 14.1 (2 x C=0) 8170.8 (0 CH₂); 60.4 (OCH₂); 20.8, 14.1 (2 x CH3). 8 170.8 (CH3); 60.4 (C-0); 20.8, 14.1 (2 x OCH₂) 8170.8 (C=0); 60.4 (OCH₂); 20.8, 14.1 (2 x CH3). 8170.8 (C) ; 60.4 (O CH2); 20.8, 14.1 (2 x O CH3) -60.4293 50 -20.7902 -14.1385 [ppm] [+]