Find the equation of the plane tangent to the surface S at (2, 3, 3) where S is parameterized by x = 2u²v², y = u +2v, z = 2u + v.
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- Find an equation of the tangent plane to the surface z = -3x? + 3y – 2x + 2y + 2 at the point (2, 1, -9). = ZFind the equation of the tangent plane to the surface 2= 4 + 3y + 7zy at the point (0,-1, 3).Find the equations of the tangent plane and normal line to the surface with equation 9y? + 9z2 = 22 – r² at the point (2, 1, 1).
- Find an equation of the tangent plane to the surface z = -2z2 - 2y2 - 1z - 2y + 3 at the point (5, 1, -56).Find the equation = 3x² + 4y² + 9xy at the point (2, 0, 12). 2 = of the tangent plane to the surfaceFind an equation for the plane tangent to the surface 9x +4y² +9z? = 34 at the point (1,2,-1).
- Find the equation of the tangent plane to the surfaceln(x3 + y3 + z3) = x2z + 1at the point (1, 1, −1).Find the equation of the tangent plane to the surface z = at the point (2,-3, 10) O - 6y - z = 10 O * + 6y – z = –26 Or+ 4y-z = -20 X- 4y- z = 4Find the equation of the plane tangent to the surface z = 3x² + y³ at (1, 1, 4).