'Find a function f such that Vf = 4x²i + 3y²j. f= Use ƒ to evaluate: [(4x²i+ 3y²j) - dr = Σ + K Σ where C is the arc of the parabola y = 1- x² from (0, 1) to (2, -3). Use ƒ to evaluate: √(4x²i + 3y²j) · dr = where D is the straight line from (0, 1) to (2, -3). Use ƒ to evaluate: [ (4x²i + 3y²j) • dr = where E is your favorite curve from (0, 1) to (2, -3). M

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 18RE
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Must solve the question completely. Don't solve partially. Skip it pls if u don't want to solve it completely. 

f=
'Find a function f such that Vf = 4x²i + 3y²j.
Use fto evaluate:
√ (4x²
(4x²i + 3y²j). dr =
√ (4x² 1 +
Σ + K
where C is the arc of the parabola y = 1x² from (0, 1) to (2, -3).
Usef to evaluate:
(4x²i+ 3y²j) dr =
Σ
where D is the straight line from (0, 1) to (2, -3).
Use ƒ to evaluate:
√(4x²i + 3y²j). dr =
20 (
Σ
where E is your favorite curve from (0, 1) to (2, -3).
If you don't get this in 3 tries, you can see a similar example (online). However, try to use this as a last resort or after you have already solved the problem. There are no See
Similar Examples on the Exams!
Transcribed Image Text:f= 'Find a function f such that Vf = 4x²i + 3y²j. Use fto evaluate: √ (4x² (4x²i + 3y²j). dr = √ (4x² 1 + Σ + K where C is the arc of the parabola y = 1x² from (0, 1) to (2, -3). Usef to evaluate: (4x²i+ 3y²j) dr = Σ where D is the straight line from (0, 1) to (2, -3). Use ƒ to evaluate: √(4x²i + 3y²j). dr = 20 ( Σ where E is your favorite curve from (0, 1) to (2, -3). If you don't get this in 3 tries, you can see a similar example (online). However, try to use this as a last resort or after you have already solved the problem. There are no See Similar Examples on the Exams!
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